Question

Solve each system of linear equations using the elimination mehod

Answer 1

Answer:

solution:  x = 4, y = 1 or (4, 1)

Step-by-step explanation:

To solve the system of linear equations using the elimination method, simply add both equations together (since the coefficeints of x have opposite signs):

-8x + 10y = -22

+ 8x -  15y =  17

       - 5y  = -5

Divide both sides by -5 to solve for y:

$\frac{-5y}{-5} = \frac{-5}{-5}$

y = 1

Next, substitute the value of y into one of the equations to solve for x:

-8x + 10y = -22

-8x + 10(1) = -22

-8x + 10 = -22

Subtract 10 from both sides

-8x + 10 - 10 = -22 - 10

-8x = -32

Divide both sides by -8 to solve for x:

$\frac{-8x}{-8} = \frac{-32}{-8}$

x = 4

Therefore, the solutions to the given systems of linear equations are: x = 4, y = 1 or (4, 1).

Answer 2

Answer: y = 1 and x = 4

Step-by-step explanation:

-8x + 10y = -22

8x - 15y = 17

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- 5y = -5 Add the two equations to eliminate x

y = 1 Solve for y

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8x - 15y = 17 (y = 1) Use y=1 in either equation

8x - 15 = 17

8x = 32

x = 4 Ta da