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Monica [59]
3 years ago
9

Find the size of angle of cuz give your answer to 1 decimal place 13cm and 4cm

Mathematics
1 answer:
liberstina [14]3 years ago
5 0

Step-by-step explanation:

<h2>2.1</h2><h2><em><u>that's</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>answer</u></em><em><u>.</u></em></h2><h2><em><u>thank</u></em><em><u> you</u></em><em><u>.</u></em></h2>
You might be interested in
A scale of the Golden Gate Bridge in San Francisco Bay has
lora16 [44]

Answer:

2520ft

Step-by-step explanation:

Calculation for what is the scale of the model?

Let x will be the span length

Hence,

x= 4200 feet long/20 inches long

x=210

Thus:

1 inch = 210 ft

1 ft = 2520

=2520ft

Therefore the scale of the model will be 2520ft

3 0
3 years ago
The net worthw(t) of a company is growing at a rate of′(t) = 2000−121t2dollarsper year, wheretis in years since 1990.(a) If the
stiv31 [10]

Answer:

The worth of the company in 2000 is $56,000.

Step-by-step explanation:

The growth rate of the company is:

f'(t)=2000-12t^{2}

To determine the worth of the company in 2000, first compute the change in the net worth during the period 1990 (<em>t</em> = 0) to 2000 (<em>t</em> = 10) as follows:

\int\limits^{10}_{0} {2000-12t^{2}} \, dt =\int\limits^{10}_{0} {2000} \, dt-12\int\limits^{10}_{0} {t^{2}} \, dt=2000 |t|^{10}_{0}-12|\frac{t^{3}}{3}|^{10}_{0}\\=(2000\times10)-(4\times10^{3})\\=20000-4000\\=16000

The increase in the company's net worth from 1990 to 2000 is $16,000.

If the company's worth was $40,000 in 1990 then the worth of the company in 2000 is:

Worth in 2000 = Worth in 1990 + Net increase in company's worth

                        =40000+16000\\=56000

Thus, the worth of the company in 2000 is $56,000.

4 0
3 years ago
The ratio of white chocolate to dark chocolate sold at a candy shop was 4 : 3. If there were 20 bars of white chocolate sold, ho
Ksju [112]

Answer:

15

Step-by-step explanation:

if the white chocolate is the 4 you would need to multiply it by 5 to get 20 so if u multiply 3 by 5 you get 15 hope this helps :)

5 0
3 years ago
Can someone tell me the formula i would use for this and how to solve through?
timama [110]
Since they are congruent, cpctc,
just set the congruent parts equal to each other. 
so 2x-20=30
and
15=3y-9
3 0
3 years ago
What is the y-value of the vertex of the function f(x)=-(x-3)(x+11)
lutik1710 [3]

so, this is a quadratic equation, meaning two solutions, and we have a factored form of it, meaning you can get the solutions by simply zeroing out the f(x).

\bf \stackrel{f(x)}{0}=-(x-3)(x+11)\implies 0=(x-3)(x+11)\implies x= \begin{cases} 3\\ -11 \end{cases} \\\\\\ \boxed{-11}\stackrel{\textit{\large 7 units}}{\rule[0.35em]{10em}{0.25pt}}-4\stackrel{\textit{\large 7 units}}{\rule[0.35em]{10em}{0.25pt}}\boxed{3}

so the zeros/solutions are at x = 3 and x = -11, now, bearing in mind the vertex will be half-way between those two, checking the number line, that midpoint will be at x = -4, so the vertex is right there, well, what's f(x) when x = -4?

\bf f(-4)=-(-4-3)(-4+11)\implies f(-4)=7(7)\implies f(-4)=49 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{vertex}{(-4~~,~~49)}~\hfill

7 0
3 years ago
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