Find the size of angle of cuz give your answer to 1 decimal place 13cm and 4cm

Mathematics

1 answer:

liberstina [14]3 years ago

5 0

Step-by-step explanation:

<h2>2.1</h2><h2>that's the answer.</h2><h2>thank you.</h2>

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All of the following statements about learning are true EXCEPT __

Rasek [7]

Craming last minute can lead to unecessary confusion however most examinars dont allow asking questions during exam

So if asking questions for clarification is allowed. A) is the odd one out

And these options are rather for test taking than learning

3 0

3 years ago

Please any help is necessary

Ugo [173]

Answer:

Option D. 50 ft

Step-by-step explanation:

we know that

The area of the figure is equal to the area of three rectangles

$A=18x+(48-36)(32-11)+(18)(32)$

$A=18x+(12)(21)+(18)(32)\\A=18x+828$

Remember that the area is given

$A= 1,728\ ft^2$

$18x+828=1,728$

solve for x

$18x=1,728-828\\18x=900\\x=50\ ft$

3 0

3 years ago

two cars travel at same speed to different destinations. car A reaches its destination in 24 minutes. car B reaches its destinat

Harlamova29_29 [7]

Answer:

The speeds of the cars is: 0.625 miles/minute

Step-by-step explanation:

We use systems of equations in two variables to solve this problem.

Recall that the definition of speed (v) is the quotient of the distance traveled divided the time it took : $v=\frac{distance}{time}$ . Notice as well that the speed of both cars is the same, but their times are different because they covered different distances. So if we find the distances they covered, we can easily find what their speed was.

Writing the velocity equation for car A (which reached its destination in 24 minutes) is:

$v\,*\,24\,min=d_A$

Now we write a similar equation for car B which travels 5 miles further than car A and does it in 32 minutes:

$v\,*\,32\,min=d_A+5\,miles$

Now we solve for $d_A$ in this last equation and make the substitution in the equation for car A:

$v\,*\,32\,min=d_A+5\,miles\\d_A=v\,*\,32\,min-5\,miles\\\\v\,*\,24\,min=v\,*\,32\,min-5\,miles\\v\,(24\,min-32\,min)=-5\,miles\\v\,(-8\,min)=-5\, miles\\v=\frac{-5}{-8} \frac{miles}{min} \\v=0.625\,\frac{miles}{min}$