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dlinn [17]
3 years ago
6

P(x) is a polynomial. Here are a few values of P(x). P(-2)=1, P(-1)=3, P(1)=0, P(2)=4.

Mathematics
1 answer:
goldfiish [28.3K]3 years ago
6 0
Dudbsusvsyans shs sis wow wiz sis wiej7251443828/).?;$;
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What is the initial value in the equation f(x) = 350(1 - 0.12)^x? *
kvasek [131]

Given:

The function is:

f(x)=350(1-0.12)^x

To find:

The initial value of the function.

Solution:

We have,

f(x)=350(1-0.12)^x

The value of the function at x=0 is called the initial value of the function.

For x=0, we get

f(0)=350(1-0.12)^0

f(0)=350(0.88)^0

Clearly 0.88 is a non zero number and zero to the power of a non zero number is always 1.

f(0)=350(1)

f(0)=350

Therefore, the initial value of the function is 350.

5 0
3 years ago
I need help and how you got that answer
anastassius [24]

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3. Add them up

21 + 28 = 49

Answer: 49

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2 years ago
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Radda [10]
<span>8x^2-8x-13 is the correct answer </span>
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3 years ago
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