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s344n2d4d5 [400]

3 years ago

7

Find the area bounded by the curve y = x1/2 + 2 the x - axis, and the lines x = 1 and x = 4?

1 answer:

Serggg [28]3 years ago

8 0

The area is given by

$\displaystyle\int_1^4(x^{1/2}+2)\,\mathrm dx=\left(\frac23x^{3/2}+2x\right)\bigg|_{x=1}^{x=4}=\dfrac{40}3-\dfrac83=\dfrac{32}3=10+\dfrac23$

so the answer is B

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The largest part of landfills is made up of newspapers. A 30.48 cm stack of newspapers weighs about 15.87 kg. How many grams doe

Helga [31]

<span>First find how many grams are in 15.87kg and how many meters are in 30.48cm

15.87kg x 1000g/kg = 15, 870g
30.49cm x 1m/100cm = 0.3049m

Then, set up a proportion.

0.3049m/15, 870g = 1m/x g

Cross multiply to get..
0.3049x = 15, 870

Divide for x and there you are.</span>Source(s):Myself.1004 <span>· 8 years ago

</span>

7 0

3 years ago

Read 2 more answers

Find the length of the indicated triangle

lions [1.4K]

Answer:

$35\ units$

Step-by-step explanation:

$We\ are\ given\ that,\\Side\ JK=(4x+19)\\Side\ KL=(9x-1)\\Now, By\ observing\ the\ triangle, we\ notice\ that\ \angle K = \angle L = \angle J.\\ Hence,\triangle JKL\ is\ an\ equilateral\ triangle\ as\ all\ its\ angles\ are\ equal.\\Hence,\\Another\ property\ of\ an\ equilateral\ triangle\ is\ its\ sides\ are\ equal\ too.\\Hence,\\Side\ JK= Side\ KL= Side\ JL\\Hence,\\By\ focusing\ only\ over\ the\ Sides\ JK\ and KL,\\(4x+19)=(9x-1)\\Hence,\\By\ solving\ the\ equation,\\4x+19=9x-1\\$

$19+1=9x-4x\\By\ using\ the\ Symmetric\ Property\ Of\ Equation,\\9x-4x=19+1\\Hence,\\5x=20\\x=4\\Now,\\As\ KL=(9x-1)\\By\ substituting\ x=4\ in\ (9x-1) ,\\9*4-1\\=36-1\\=35$

8 0

2 years ago

A child rides his bicycle at 6m/s for 80 minutes. What is his distance?Don't forget the units.

kaheart [24]

13 miles or you could say 13.3 miles

5 0

2 years ago

I need help please.

avanturin [10]

7y2+2y2+3-6y2-3y2-4
7y2+6y2+2y-3y+3-4
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4 0

3 years ago

Read 2 more answers

A.) pinky bought 1 1/2 kg of apples and 5 1/4 kg of mangoes and 1 1/2 Kg of oranges. Find the total weight of fruits B.) If her

Natasha2012 [34]

Answer:

a) The total weight of fruits is $8\,\frac{1}{4}$ kilograms, b) The weight of the fruits left is $4\,\frac{1}{2}$ kilograms.

Step-by-step explanation:

a) The total weight of fruits ( $m_{T}$ ) is calculated by the following formula:

$m_{T} = m_{a} + m_{m}+m_{o}$

Where:

$m_{a}$ - Total weight of apples, measured in kilograms.

$m_{m}$ - Total weight of mangoes, measured in kilograms.

$m_{o}$ - Total weight of oranges, measured in kilograms.

If $m_{a} = 1\,\frac{1}{2} \,kg$ , $m_{m} = 5\,\frac{1}{4}\,kg$ and $m_{o} = 1\,\frac{1}{2}\,kg$ , then:

$m_{T} = 1\,\frac{1}{2}\,kg + 5\,\frac{1}{4}\,kg + 1\,\frac{1}{2}\,kg$

$m_{T} = \frac{6}{4}\,kg + \frac{21}{4}\,kg + \frac{6}{4}\,kg$

$m_{T} = \frac{33}{4}\,kg$

$m_{T} = 8\,\frac{1}{4}\,kg$

The total weight of fruits is $8\,\frac{1}{4}$ kilograms.

b) The weight eaten by her family is determined by the following expression:

$m_{E} = m_{a,e} + m_{m,e} + m_{o,e}$

Where:

$m_{a,e}$ - Eaten weight of apples, measured in kilograms.

$m_{m,e}$ - Eaten weight of mangoes, measured in kilograms.

$m_{o,e}$ - Eaten weight of oranges, measured in kilograms.

Given that $m_{a,e} = \frac{3}{4}\,kg$ , $m_{m,e} = 2\,\frac{1}{2}\,kg$ and $m_{o,e} = \frac{1}{2}\,kg$ , the weight eaten by her family is:

$m_{E} = \frac{3}{4}\,kg + 2\,\frac{1}{2}\,kg + \frac{1}{2}\,kg$

$m_{E} = \frac{3}{4}\,kg + \frac{10}{4}\,kg + \frac{2}{4}\,kg$

$m_{E} = \frac{15}{4}\,kg$

$m_{E} = 3\,\frac{3}{4}\,kg$

The weight of the fruits left is found by subtraction:

$m_{R} = m_{T}-m_{E}$

$m_{R} = 8\,\frac{1}{4} \,kg -3\,\frac{3}{4}\,kg$

$m_{R} = \frac{33}{4}\,kg-\frac{15}{4}\,kg$

$m_{R} = \frac{18}{4}\,kg$

$m_{R} = 4 \,\frac{1}{2}\,kg$

The weight of the fruits left is $4\,\frac{1}{2}$ kilograms.

3 0

3 years ago