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DerKrebs [107]
3 years ago
12

HELP! DUE SOON! X^2=6

Mathematics
1 answer:
Mariulka [41]3 years ago
7 0

Answer:

x² = 2

x = sqrt. of 6

x = (+-)2.449

Step-by-step explanation:

brainliest plz

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Solve the elimination method
vlada-n [284]

Answer:

C)No Solution

Step-by-step explanation:

Given  2 equations

  • 4x-2y=1
  • 2x-y=2

Mentioned to solve using eliminations method

4x-2y=1

2x-y=2

Multiply second equation with 2

⇒second equation is 4x-2y=4

Now subtract second equation from 1st equation

4x-2y-(4x-2y)=1-4

4x-4x-2y+2y=-3

0+0=3

0=3

But 0≠3

Therefore there exists no solutions for the given pair of equations

Both equations are Parallel lines as they have the same slope

7 0
3 years ago
Simplify: (Algebra)
kodGreya [7K]

Answer:

2j-3o-5e+l-j+4o+6e= e+j+l+o

-7d+a+2v-i+8d-v+2i+d^2 = d^2+a+d+i+v

4a+12r-i+a^2-11r-3a+n+a^3 = a^3+a^2+a-i+n+r

r^3-11a+12a-sh+2sh+i+d= r^3+a+sh+i+d

t^5+a-2a+2r-r+l-2l+a^4+3n-2n = t^5-a+r-l+a^4+n

-11i^2-r+2r+a^3-4d+3d-a = -11i^2+r+a^3-d-a

-9r+10r+a-s^3-2a+2s^3+u-l = r-a+s^3+u-l

-4d+2a^3-a^3+5n+iz-4n = -4d+a^3+n+iz

16a^5-2(l-y+y3)-a+d^2-d^3+in = 16a^5-2l-2y+2y3-a+d^2-d^3+in

-5z-e+2e-y^5-n+2n-a^5-l+l^3-i^3 = -5z+e-y^5+n-a^5-l+l^3-i^3

-2m+a-m^3-2m^5-a^3-d+l+i^4= -2m+a-m^3-2m^5-a^3-d+l+i^4

-4t^3+5t^3+3o-2o+2m-m-r^3-is+2is = t^3+o+m-r^3+is

-5j+h-2h+4j-3a+6a-d^3 = -5j-h+4j+3a-d^3

r^3-3u+2u-st+a^3-2a^3-5m+4m = r^3-u-st-a^3-m

-6b^5-a+4h-3h+18a^2+3a-d^4+i^2-2i^2-4r^4= -6b^5+3a-a+4h-3h+18a^2-d^4+i^2-2i^2-4r^4

13s^5-2o+5n^3-12s^5-6n^3+3o+a^5=s^5+o-n^3+a^5

-17m+16m-3u+r^3+2u-2r^3+a^4+d^4= -1m+-u-r^3+a^4+d^4

Step-by-step explanation:

a.\ 2j-3o-5e+l-j+4o+6e

Collect Like Terms

-5e+6e+2j-j+l+4o-3o

e+j+l+o

Hence:

2j-3o-5e+l-j+4o+6e= e+j+l+o

b.\ -7d+a+2v-i+8d-v+2i+d^2

Collect Like Terms

d^2+a+8d-7d-i+2i+2v-v

d^2+a+d+i+v

Hence:

-7d+a+2v-i+8d-v+2i+d^2 = d^2+a+d+i+v

c.\ 4a+12r-i+a^2-11r-3a+n+a^3

Collect Like Terms

a^3+a^2+4a-3a-i+n+12r-11r

a^3+a^2+a-i+n+r

Hence:

4a+12r-i+a^2-11r-3a+n+a^3 = a^3+a^2+a-i+n+r

d.\ r^3-11a+12a-sh+2sh+i+d

Evaluate like terms

r^3+a+sh+i+d

Hence:

r^3-11a+12a-sh+2sh+i+d= r^3+a+sh+i+d

e.\ t^5+a-2a+2r-r+l-2l+a^4+3n-2n

Evaluate like terms

t^5-a+r-l+a^4+n

Hence:

t^5+a-2a+2r-r+l-2l+a^4+3n-2n = t^5-a+r-l+a^4+n

f.\ -11i^2-r+2r+a^3-4d+3d-a

Evaluate Like Terms

-11i^2+r+a^3-d-a

Hence:

-11i^2-r+2r+a^3-4d+3d-a = -11i^2+r+a^3-d-a

g.\ -9r+10r+a-s^3-2a+2s^3+u-l

Collect Like Terms

-9r+10r+a-2a+2s^3-s^3+u-l

r-a+s^3+u-l

Hence:

-9r+10r+a-s^3-2a+2s^3+u-l = r-a+s^3+u-l

h.\ -4d+2a^3-a^3+5n+iz-4n

Collect Like Terms

-4d+2a^3-a^3+5n-4n+iz

-4d+a^3+n+iz

Hence:

-4d+2a^3-a^3+5n+iz-4n = -4d+a^3+n+iz

i.\ 16a^5-2(l-y+y3)-a+d^2-d^3+in

Open bracket

16a^5-2l-2y+2y3-a+d^2-d^3+in

Hence:

16a^5-2(l-y+y3)-a+d^2-d^3+in = 16a^5-2l-2y+2y3-a+d^2-d^3+in

j.\ -5z-e+2e-y^5-n+2n-a^5-l+l^3-i^3

Evaluate like terms

-5z+e-y^5+n-a^5-l+l^3-i^3

Hence:

-5z-e+2e-y^5-n+2n-a^5-l+l^3-i^3 = -5z+e-y^5+n-a^5-l+l^3-i^3

k.\ m-3m-a+2a-m^3-2m^5-a^3-d+l+i^4

Evaluate like terms

-2m+a-m^3-2m^5-a^3-d+l+i^4

Hence:

-2m+a-m^3-2m^5-a^3-d+l+i^4= -2m+a-m^3-2m^5-a^3-d+l+i^4

l.\ -4t^3+5t^3+3o-2o+2m-m-r^3-is+2is

Evaluate like terms

t^3+o+m-r^3+is

Hence

-4t^3+5t^3+3o-2o+2m-m-r^3-is+2is = t^3+o+m-r^3+is

m.\ -5j+h-2h+4j-3a+6a-d^3

Evaluate like terms

-5j-h+4j+3a-d^3

Hence:

-5j+h-2h+4j-3a+6a-d^3 = -5j-h+4j+3a-d^3

n.\ r^3-3u+2u-st+a^3-2a^3-5m+4m

Evaluate like terms

r^3-u-st-a^3-m

Hence:

r^3-3u+2u-st+a^3-2a^3-5m+4m = r^3-u-st-a^3-m

o.\ -6b^5-a+4h-3h+18a^2+3a-d^4+i^2-2i^2-4r^4

Collect Like Terms

-6b^5+3a-a+4h-3h+18a^2-d^4+i^2-2i^2-4r^4

-6b^5+2a+h+18a^2-d^4-i^2-4r^4

Hence:

-6b^5-a+4h-3h+18a^2+3a-d^4+i^2-2i^2-4r^4= -6b^5+3a-a+4h-3h+18a^2-d^4+i^2-2i^2-4r^4

p.\ 13s^5-2o+5n^3-12s^5-6n^3+3o+a^5

Collect Like Terms

13s^5-12s^5-2o+3o+5n^3-6n^3+a^5

s^5+o-n^3+a^5

Hence:

13s^5-2o+5n^3-12s^5-6n^3+3o+a^5=s^5+o-n^3+a^5

q.\ -17m+16m-3u+r^3+2u-2r^3+a^4+d^4

Collect Like Terms

-17m+16m+2u-3u+r^3-2r^3+a^4+d^4

-m+-u-r^3+a^4+d^4

Hence:

-17m+16m-3u+r^3+2u-2r^3+a^4+d^4= -1m+-u-r^3+a^4+d^4

7 0
3 years ago
Which expression gives the same result as ∑4i=0(5)(1/3)i?
valina [46]
I'm assuming which expression gives the same result as ∑^4The choices are:i=0^(5) (1/3)^i
The second option is correct since the first option is erroneous or makes little sense. The second option and the ∑^4 are geometric progressions which will account for each other when substituted together or one into another.
 
8 0
4 years ago
Read 2 more answers
Given that F(x)=x2+2, evaluate F(2) <br> A)0<br> B)2<br> C)6
nekit [7.7K]
<span>F(x)=x^2+2
so
F(2) = 2^2 + 2 = 4 + 2 = 6

answer
</span><span>C)6</span>
8 0
4 years ago
The Highest Common Factor of three numbers is 6 and the Lowest Common Multiple is 24 What are the three numbers?​(PLEASE HELP)
Arlecino [84]

Answer:

the three numbers most probably are 12, 8, 6

Step-by-step explanation:

LCM of these three number is 24.; ( 12x2, 8x3, 6x4)

out of these three numbers 12 has the highest common factor which is 6. because 6x2 is 12. if you compare the other two they have a common factor less than 6.

7 0
3 years ago
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