$\overrightarrow{P_1P_2}=(P_2-P_1)\cdot(\textbf{i},\textbf{j},\textbf{k})=(-5-0)\textbf{i}+(-3-1)\textbf{j}+(-9-(-3))\textbf{k}\\\\\overrightarrow{P_1P_2}=-5\textbf{i}-4\textbf{j}-6\textbf{k}$

3 0

4 years ago

Two numbers have a sum of 20 and a difference of 16 what are the two numbers

HACTEHA [7]

A. 18+2 = 20 abs 18-2= 17

8 0

3 years ago

Use the strategy to simplify 4\sqrt(576)<br> Write the prime factorization of the radicand.

Ronch [10]

<h3>Answer: 96</h3>

===================================================

Work Shown:

$4\sqrt{576}\\\\4\sqrt{2*2*2*2*2*2*3*3}\\\\4\sqrt{(2*2)*(2*2)*(2*2)*(3*3)}\\\\4\sqrt{(2)^2*(2)^2*(2)^2*(3)^2}\\\\4\sqrt{(2*2*2*3)^2}\\\\4\sqrt{24^2}\\\\4*24\\\\96\\\\$

6 0

3 years ago

Read 2 more answers