
<u>Mona starts from 68th stone</u>
<u>She jumps</u><u> </u><u>23</u><u> </u><u>stones</u><u> </u><u>ahead</u><u> </u>
<u>Then</u><u> </u><u>she</u><u> </u><u>jumps</u><u> </u><u>28</u><u> </u><u>stones</u><u> </u><u>back</u>

<em>Her final position=?</em>




- To find how much stones she is ahead or back we will Subtract 63 from 68 which was her initial position.

So, Mona will be <em><u>5</u></em><em><u> </u></em><em><u>stones</u></em><em><u> </u></em><em><u>behind</u></em><em><u> </u></em><em><u>from</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>starting</u></em><em><u> </u></em><em><u>stone</u></em><em><u>.</u></em>
☯️Hence, Option C is correct
Answer:
See explanation
Step-by-step explanation:
Given two expressions

and

Substitute y = 5 into each expression:
1.

2.

As you can see the results are the same.
When you say she'll you are saying she will, she is like a statement you make for yourself like I shall be on my way to Tokyo. I don't know if this helps because I couldn't quite understand your problem
The two factors are 3 and 8.
There are 5 terms in each factor of this expression.
The coefficient of the variable term is 3.
Hope this helps!