Answer:
def countdown(n):
if n <= 0:
print('Blastoff!')
else:
print(n)
countdown(n-1)
def countup(n):
if n >= 0:
print('Blastoff!')
else:
print(n)
countup(n+1)
number = int(input("Enter a number: "))
if number >= 0:
countdown(number)
elif number < 0:
countup(number)
<u>Outputs:</u>
Enter a number: 3
3
2
1
Blastoff!
Enter a number: -3
-3
-2
-1
Blastoff!
Enter a number: 0
Blastoff!
For the input of zero, the countdown function is called.
Explanation:
Copy the countdown function
Create a function called countup that takes one parameter, n. The function counts up from n to 0. It will print the numbers from n to -1 and when it reaches 0, it will print "Blastoff!".
Ask the user to enter a number
Check if the number is greater than or equal to 0. If it is, call the countdown function. Otherwise, call the countup function.
Is this for a test, because someone else asked that.
Answer:b)convergence.
Explanation: Convergence has the basic meaning as when two or more unit of anything meet to converge or join. In the research , the different types of the tools are brought togather and skills and compare them.The measurement is done through the tools which has the already defined parameters.
Thus this concept is the example of the convergence because the tools are being converged and compared.so, the correct answer is option (B) and other option are incorrect because they have the technique of the contrasting and separation and reading respectively.
Answer:
The answer is "is mostly empty space".
Explanation:
In the given question option numbers is defined, so the explanation to this question as follows:
The volume of an element holds one mole at high temperatures. The nuclear mass is usually indicated by mole: cc/mol in the
. It is also known as a quantity, in which the same molecule was the measured values based on atomic mass as well as the thickness of both, and certain alternatives were wrong which can be explained as follows:
- atom doesn't fill the protons, neutrons, and electrons.
- It can't revolve with outside atoms and electrons.