All categories

3 years ago

HELP PLEASE! I need the answer please!

Mathematics

1 answer:

cestrela7 [59]3 years ago

7 0

Answer:

The triangles are similar in that the smaller triangle was dilated by a scale factor of 1/4 which means that the length of the missing side is 20m

Step-by-step explanation:

You might be interested in

Find the value of t in parallelogram FGHI. H 2t+6 G I Зt-6 t =

hammer [34]

Answer:

i dont know'

Step-by-step explanation:

3 0

3 years ago

I need some answers please please please

8_murik_8 [283]

Answer:

what does slope mean?

4 0

3 years ago

Read 2 more answers

Pls help math problem

IgorLugansk [536]

Answer:

angle plm+angle lpm+angle pml=180°[by angle sum property]

21°+angle lpm+38°=180°

59°+ lpm=180°

lpm=180°-59°

lpm=121°

lpm+npl=180°[by limear pair]

121°+npl=180°

npl=180°-121°

npl=59°

5 0

3 years ago

The volume of a rectangular box with a square base remains constant at 500 cm3 as the area of the base increases at a rate of 10

serious [3.7K]

Answer:

The rate of change of the height of the box at which is decreasing is $\frac{5000}{130321}$ centimeters per second.

Step-by-step explanation:

From Geometry the volume of a rectangular box ( $V$ ), measured in cubic centimeters, with a square base is modelled by the following formula:

$V = A_{b}\cdot h$ (Eq. 1)

Where:

$A_{b}$ - Area of the base, measured in square centimeters.

$h$ - Height of the box, measured in centimeters.

The height of the box is cleared within the formula:

$h = \frac{V}{A_{b}}$

If we know that $V = 500\,cm^{3}$ and $A_{b} = 361\,cm^{2}$ , then the current height of the box is:

$h = \frac{500\,cm^{3}}{361\,cm^{2}}$

$h = \frac{500}{361}\,cm$

The rate of change of volume in time ( $\frac{dV}{dt}$ ), measured in cubic centimeters per second, is derived from (Eq. 1):

$\frac{dV}{dt} = \frac{dA_{b}}{dt}\cdot h + A_{b}\cdot \frac{dh}{dt}$ (Eq. 2)

Where:

$\frac{dA_{b}}{dt}$ - Rate of change of the area of the base in time, measured in square centimeters per second.

$\frac{dh}{dt}$ - Rate of change of height in time, measured in centimeters per second.

If we get that $\frac{dV}{dt} = 0\,\frac{cm^{3}}{s}$ , $\frac{dA_{s}}{dt} = 10\,\frac{cm^{2}}{s}$ , $h = \frac{500}{361}\,cm$ and $A_{b} = 361\,cm^{2}$ , then the equation above is reduced into this form:

$0\,\frac{cm^{3}}{s} = \left(10\,\frac{cm^{2}}{s} \right)\cdot \left(\frac{500}{361}\,cm \right)+(361\,cm^{2})\cdot \frac{dh}{dt}$

Then, the rate of change of the height of the box at which is decreasing is:

$\frac{dh}{dt} = -\frac{5000}{130321}\,\frac{cm}{s}$

The rate of change of the height of the box at which is decreasing is $\frac{5000}{130321}$ centimeters per second.

5 0

3 years ago

The length of a room is 18

Virty [35]

Question:

The length of a room is 18 1 /2 feet. If using 1 /4 inch = 1 foot scale, what would be the length of a wall on a blueprint of a floor plan?

Answer:

The length of a wall on a blueprint of a floor plan is $4.625 \text{ or } 4\frac{5}{8} \text{ inches }$

Solution:

Given that,

$Length\ of\ room = 18\frac{1}{2} \text{ feet }\\\\Length\ of\ room = 18.5 \text{ feet }$

The scale given is:

$\frac{1}{4}\ inch = 1\ foot$

To find: Length of a wall on a blueprint of a floor plan

Let "x" be the length of a wall on a blueprint of a floor plan

Then from given,

$\frac{1}{4}\ inch = 1\ foot\\\\x\ inches = 18.5\ feet$

This forms a proportion and we can solve by cross multiplying

$\frac{1}{4} \times 18.5 = x \times 1\\\\x = 4.625\\\\In\ terms\ of\ mixed\ fraction,\\\\x = 4\frac{5}{8}$

Thus length of a wall on a blueprint of a floor plan is $4.625 \text{ or } 4\frac{5}{8} \text{ inches }$

3 0

3 years ago

Read 2 more answers

HELP PLEASE! I need the answer please! ​

HELP PLEASE! I need the answer please!