Option c is correct. Use special right triangles and you will findout why. Hint:Use the 45-45-90 special right triangle's properties.
Answer:
Step-by-step explanation:
Hello, please consider the following.
![3\cdot 4^n+51=3\cdot 4^n+3\cdot 17=3(4^n+17)](https://tex.z-dn.net/?f=3%5Ccdot%204%5En%2B51%3D3%5Ccdot%204%5En%2B3%5Ccdot%2017%3D3%284%5En%2B17%29)
So this is divisible by 3.
Now, to prove that this is divisible by 9 = 3*3 we need to prove that
is divisible by 3. We will prove it by induction.
Step 1 - for n = 1
4+17=21= 3*7 this is true
Step 2 - we assume this is true for k so
is divisible by 3
and we check what happens for k+1
![4^{k+1}+17=4\cdot 4^k+17=3\cdot 4^k + 4^k+17](https://tex.z-dn.net/?f=4%5E%7Bk%2B1%7D%2B17%3D4%5Ccdot%204%5Ek%2B17%3D3%5Ccdot%204%5Ek%20%2B%204%5Ek%2B17)
is divisible by 3 and
is divisible by 3, by induction hypothesis
So, the sum is divisible by 3.
Step 3 - Conclusion
We just prove that
is divisible by 3 for all positive integers n.
Thanks
Answer:
Step-by-step explanation:
13p⁵ + 6p - 12p² -(-9p - p² - 13p⁵) = 13p⁵ + 6p - 12p² + 9p + p² + 13p⁵
{Distribute (-1) to the second expression}
= <u>13p⁵ + 13p⁵</u> <u>-12p² + p²</u> <u>+ 6p + 9p</u>
{Combine like terms}
= 26p⁵ - 11p² + 15p