The first answer is correct. There are no outliers because all of these numbers exist within the same range. For example the number 6 would be a outlier in this case because it ranges so far from the other numbers in the data. There are clusters because clusters are the opposite of outliers. The numbers cluster together or group together.
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Answer:
1) If 3 is an odd number, then 3 times 3 is an even number.
False because multiplying odd number by an odd number also gives an odd number.
2) If 6 is less than 7, then 4 is greater than 7.
False because 4 is smaller than 6. As 6 is smaller than 7 then 4 must also be smaller.
3) Six is divisible by 3, and 10 is a multiple of 2.
True. 6/3 = 2 and 2 x 5 = 10. Both the conditions are true so it is also true.
4) The average of the data is greater than the largest value in the data, or it’s less than the largest value in the data.
True.
We have two conditions in this statement and an 'or' between them. One of the conditions is true that is "average is less than the largest value in the data". So the statement as a whole is true.
5) The slope of a linear graph is its rate of change, and the graph’s y-intercept is the initial value.
True.
6) If an equilateral triangle has equal angles, then all its angles will measure 45°.
False.
A triangle has 3 angles whose sum = 180 degrees.
For equilateral triangle each angle will measure 180/3= 60 degrees.
We know that
the equation of the line in <span>slope-intercept form--------------> y=mx+b
Part A)
</span>Passing through (2,5) and perpendicular to the line whose equation is -3x+y-6=0
<span>Step 1
find the slope m
</span><span>remember that if two lines are perpendicular mi*m2=-1
</span>-3x+y-6=0---------> y=3x+6-------------> m1=3
then
m2=-1/3
Step 2
find the value of b
point (2,5) m=-1/3
y=mx+b----------> 5=(-1/3)*2+b--------> b=5+(2/3)-----> b=17/3
Step 3
find the equation of the line in slope-intercept form
y=(-1/3)x+17/3
using a graph tool
see the attached figure
the answer part A) is y=(-1/3)x+17/3Part B)
Passing through (2,5) and perpendicular to the line whose equation is -3x-6=7x; slope intercept form.
Step 1
-3x-6=7x---------> 10x=-6 -----> x=-6/10-----> x=-3/5 (parallel to the axis y)
equation of the line is a constant so its perpendicular will be another constant defined by the coordinate y of the point through which it passes parallel to the axis x
point (2,5) ----------> the coordinate y=5
therefore
the perpendicular line is y=5 (parallel to the axis x)
using a graph tool
see the attached figure
the answer part B) is y=5
i) the least positive coterminal angle can be found by subtracting 2pi from your original angle. We subtract 2pi because 11pi/3 is larger than 2pi.
So: 11pi/3 - 2pi = 11pi/3 - 6pi/3 = 5pi/3 or 
ii) The reference angle is the smallest angle you can make with the x-axis. Since 5pi/3 is in Quadrant IV, the reference angle is found by:
2pi - 5pi/3 = 6pi/3 - 5pi/3 = pi/3 or 
iii) 5pi/3 or 300 degrees is found in Quadrant IV.