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2 years ago

If your not in 5th or higher grade don't answer my question

Mathematics

2 answers:

scoundrel [369]2 years ago

7 0

Answer:

ok loll

Step-by-step explanation:

dalvyx [7]2 years ago

5 0

Answer: Okay :-|

Step-by-step explanation:

You might be interested in

R is inversely proportional to A.

hjlf

Here are the answer: a) R = 3.6 and b) A = 2

Step-by-step explanation:

Given,

R is inversely proportional to A.

R ∝ $\frac{1}{A}$

so, R = $\frac{k}{A}$ -------eq 1 where k is any constant

To find the values of a) R when A = 5 and

b) Value of A when R = 9

Now,

Putting R = 12 and A = 1.5 in eq 1 we get,

12 = $\frac{k}{1.5}$

or, k = 12×1.5 = 18

From eq 1 we get,

R = $\frac{18}{A}$ --------- eq 2

Now,

a) Putting A= 5 in eq 2 we get,

R = $\frac{18}{5}$ = 3.6

b) Putting R = 9 in eq 2 we get

R = $\frac{18}{A}$

or, A = $\frac{18}{9}$ = 2

5 0

3 years ago

Read 2 more answers

Marą purchased a cell

DanielleElmas [232]

Answer: $28.30✔️

Step-by-step explanation:

Let C = cost before tax

Cell phone costs = C + C·6% = $30

C(1 + 0.06) = $30

C = $30/1.06 = $28.30

Answer: $28.30✔️

<h3> Verify </h3>

Cell phone after tax = $28.30 + $28.30·6/100 = $28.30 + $1.70 = $30✔️

<h2><em>Spymore </em></h2>

6 0

2 years ago

Drag the tiles to the boxes to form correct pairs. Not all tiles will be used. Match the pairs of polynomials to their products.

andreyandreev [35.5K]

The products of the polynomials are:

(xy + 9y + 2) * (xy - 3) = x²y² - xy + 9xy² - 27y - 6
(2xy + x + y) * (3xy² - y) = 6x²y³ - 2xy² + 3x²y² -xy + 3xy³- y²
(x - y) * (x + 3y) = x² + 2xy + 3y²
(xy + 3x + 2) * (xy – 9) = x²y² - 7xy + 3x²y - 27x - 18
(x² + 3xy - 2) * (xy + 3) = x³y + 3x² + 3x²y² + 7xy - 6
(x + 3y) * (x – 3y) = x² - 9y²

<h3>How to evaluate the products?</h3>

To do this, we multiply each pair of polynomial as follows:

(xy + 9y + 2) * (xy - 3)

Expand

(xy + 9y + 2) * (xy - 3) = x²y² - 3xy + 9xy² - 27y + 2xy - 6

Evaluate the like terms

(xy + 9y + 2) * (xy - 3) = x²y² - xy + 9xy² - 27y - 6

(2xy + x + y) * (3xy² - y)

Expand

(2xy + x + y) * (3xy² - y) = 6x²y³ - 2xy² + 3x²y² -xy + 3xy³- y²

(x - y) * (x + 3y)

Expand

(x - y) * (x + 3y) = x² + 3xy - yx + 3y²

Evaluate the like terms

(x - y) * (x + 3y) = x² + 2xy + 3y²

(xy + 3x + 2) * (xy – 9)

Expand

(xy + 3x + 2) * (xy – 9) = x²y² - 9xy + 3x²y - 27x + 2xy - 18

Evaluate the like terms

(xy + 3x + 2) * (xy – 9) = x²y² - 7xy + 3x²y - 27x - 18

(x² + 3xy - 2) * (xy + 3)

Expand

(x² + 3xy - 2) * (xy + 3) = x³y + 3x² + 3x²y² + 9xy - 2xy - 6

Evaluate the like terms

(x² + 3xy - 2) * (xy + 3) = x³y + 3x² + 3x²y² + 7xy - 6

(x + 3y) * (x – 3y)

Apply the difference of two squares

(x + 3y) * (x – 3y) = x² - 9y²