To better give a visual, I drew it out instead.
The attachment is the solution.
1: I can’t see one it’s cut out sorry :(
2:go down four horrizontal for each line making a rhombus
3: 3a:true 3b:true 3c:false 3D: false
4.PART A: Draw a square in the middle.
4. PART B: Say there are four right angles
5: Line, point, ray, line segment
6. There are 2 acute and 1 right
7. A B C
8: 1/4 1/6 1/8
9: 9a 9c and 9d
10: square and polygons first, then triangles because they have 4 sides while a triangle has 3
10 PART B: rectangles second, then the pentagons are third, the parallelogram is first, then the triangles because a rectangle has all right angles
11: she drew a square!
12: polygons without right angles
13: I can’t draw on your paper just draw three lines in the trapezoid
13: a c and d
The area of the square is obtained by taking the square of the length of one side. Since it is said that the area of the square is less than 100 m^2, taking the square root of that where: sqrt (100) = 10, the side of that square should be less than 10 as well. Among the choices, D. 0 <y <10 (where y = length of side of square) is the correct answer.
Answer:
The individual has 36.09 pounds of body fat.
Step-by-step explanation:
Given that an individual has a body fat percentage of 19.3% and weighs 187 pounds, to determine how many pounds of her weight is made up of fat the following calculation must be performed:
(187 x 19.3) / 100 = X
3.609.1 / 100 = X
36.091 = X
Therefore, the individual has 36.09 pounds of body fat.
Step-by-step explanation:
Take the first derivative
Set the derivative equal to 0.
or
For any number less than -1, the derivative function will have a Positve number thus a Positve slope for f(x).
For any number, between -1 and 1, the derivative slope will have a negative , thus a negative slope.
Since we are going to Positve to negative slope, we have a local max at x=-1
Plug in -1 for x into the original function
So the local max is 2 and occurs at x=-1,
For any number greater than 1, we have a Positve number for the derivative function we have a Positve slope.
Since we are going to decreasing to increasing, we have minimum at x=1,
Plug in 1 for x into original function
So the local min occurs at -2, at x=1
