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Anna11 [10]
2 years ago
5

Point A is located at (-2, 2). Point B is located at (-2, 0). What is the distance between point A and point B ?

Mathematics
1 answer:
Andrew [12]2 years ago
6 0

Answer:

2

Step-by-step explanation:

Both point a and b have an x value of -2 so to find the distance between the two points we simply have to find the horizontal distance. We can do this by subtract the y value of the first point by the y value of the second point.

Point A y value : 2

Point B y value : 0

Distance between Point A and Point B : 2 - 0 = 2 units

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F(x) = 3x + x3
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Please check the explanation.

Step-by-step explanation:

Given

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Taking differentiate

\frac{d}{dx}\left(3x+x^3\right)

\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'

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solving

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\mathrm{Take\:the\:constant\:out}:\quad \left(a\cdot f\right)'=a\cdot f\:'

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now solving

\frac{d}{dx}\left(x^3\right)

\mathrm{Apply\:the\:Power\:Rule}:\quad \frac{d}{dx}\left(x^a\right)=a\cdot x^{a-1}

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Thus, the expression becomes

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Thus,

f'(x) = 3 + 3x²

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substituting the value  f'(x) = 15 in f'(x) = 3 + 3x²

f'(x) = 3 + 3x²

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switch sides

3 + 3x² = 15

3x² = 15-3

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x² = 4

\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

x=\sqrt{4},\:x=-\sqrt{4}

x=2,\:x=-2

Thus, the value of x​ will be:

x=2,\:x=-2

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