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atroni [7]
2 years ago
5

Simplify x^4 * x What would be the simplified answer

Mathematics
2 answers:
kramer2 years ago
5 0

Answer: The simplified answer will be: x^5

Step-by-step explanation:

x4x

=x4*x1

=(x*x*x*x)*(x)

=x*x*x*x*x

=x^5

elena-s [515]2 years ago
3 0

Answer:

x⁵

General Formulas and Concepts:

<u>Algebra I</u>

  • Exponential Property [Multiplying]: \displaystyle b^m \cdot b^n = b^{m + n}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

x⁴ · x

<u>Step 2: Simplify</u>

  1. Exponential Rule [Multiplying]:                                                                        \displaystyle x^4 \cdot x = x^{4 + 1}
  2. Add:                                                                                                                      \displaystyle x^4 \cdot x = x^5
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Answer

27 days

Step-by-step explanation:

father= 45 days

oldest son + father=27 days

youngest + father= 36 days

45-27=18

45-36=9

18+9=27

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18 days=oldest son

9 days =youngest son

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Answer:

(3,4)

Step by step explanation:
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vladimir2022 [97]

Answer:

z=\frac{7.1-7.4}{\frac{1.2}{\sqrt{36}}}=-1.5  

Since is a left sided test the p value would be:  

p_v =P(z  

Comparing the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the true mean is significantly lower than 7.4 minutes at 10% of significance

Step-by-step explanation:

Data given and notation  

\bar X=7.1 represent the sample mean    

\sigma=1.2 represent the population standard deviation

n=36 sample size  

\mu_o =7.4 represent the value that we want to test  

\alpha=0.1 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean i lower than 7.4, the system of hypothesis would be:  

Null hypothesis:\mu \geq 7.4  

Alternative hypothesis:\mu < 7.4  

The statistic is given by

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{7.1-7.4}{\frac{1.2}{\sqrt{36}}}=-1.5  

P-value  

Since is a left sided test the p value would be:  

p_v =P(z  

Conclusion  

Comparing the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the true mean is significantly lower than 7.4 minutes at 10% of significance

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