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marysya [2.9K]
3 years ago
7

HLEP ME PLEASE !!!!!!

Mathematics
1 answer:
Advocard [28]3 years ago
7 0

Answer:

f(x) + g(x) = 3x + 7

Step-by-step explanation:

f(x) = 2x + 2, g(x) = x + 5

f(x) + g(x) = 2x + 2 +x + 5

f(x) + g(x) = 2x +x + 5 +2

f(x) + g(x) = 3x + 7

You might be interested in
The sum of the digits of a two-digit number is 12. The number formed by reversing the digits is 54 more than the original number
andreyandreev [35.5K]

Answer:

39

Step-by-step explanation:

let the 2 digit number be ab = 10a + b ( considering place value )

The reversed  2 digit number is ba = 10b + a

The sum of the 2 digit number is

a + b = 12 ( subtract b from both sides )

a = 12 - b → (1)

Expressing as an equation

ba = ab + 54 , that is

10b + a = 10a + b + 54

Substitute a = 12 - b into the equation

10b + 12 - b = 10(12 - b) + b + 54 , simplify both sides

9b + 12 = 120 - 10b + b + 54

9b + 12 = - 9b + 174 ( add 9b to both sides )

18b + 12 = 174 ( subtract 12 from both sides )

18b = 162 ( divide both sides by 18 )

b = 9

Substitute b = 9 into (1)

a = 12 - 9 = 3

Thus

the original 2 digit number = ab = 39

The reversed 2 digit number = ba = 93

which is 54 more than the original number

7 0
3 years ago
Can someone please help me with this :( asap
Rama09 [41]

b

こんにちは

mmmmmmmmnnnnnnnnnnnnnnnnnnnnnnn

7 0
3 years ago
Anec 2 Matemáticas
Rama09 [41]

Answer:

a) 1 : 100

1 cm en el mapa equivalen a 100 cm en la realidad

b) 1 : 1000

1 cm en el mapa equivalen a 1000 cm en la realidad

c) 1 : 2000

1 cm en el mapa equivalen a 2000 cm en la realidad

d) 1 : 18000

1 cm en el mapa equivalen a 18000 cm en la realidad

Step-by-step explanation:

Tenemos 4 escalas :

a) 1 : 100

b) 1 : 1000

c) 1 : 2000

d) 1 : 18000

Definimos ''escala'' como una relación entre dos números ''a'' y ''b'', generalmente ''a'' y ''b'' son números naturales. Denotamos la escala como :

a : b

En dónde ''a'' representa la longitud del dibujo y ''b'' la longitud real.

Por ende, cuando a estamos en presencia de una escala de reducción y cuando a>b estamos en presencia de una escala de ampliación.

La escala a=b ó 1 : 1 se define como escala natural.

Analicemos cada caso :

a) 1 : 100

Aquí vemos que es una escala de reducción (dado que 1 < 100) por ende cualquier magnitud de longitud en el mapa será 100 veces más grande en la vida real.

En este caso, 1 cm en el mapa equivalen a 100 cm en la realidad.

Análogamente y con el mismo razonamiento, escribimos las relaciones para los casos b), c) y d)  

b) 1 cm en el mapa equivalen a 1000 cm en la vida real

c) 1 cm en el mapa equivalen a 2000 cm en la vida real

d) 1 cm en el mapa equivalen a 18000 cm en la vida real

b), c) y d) también representan escalas de reducción.

7 0
3 years ago
Assume that there are an equal number of births in each month so that the probability is that a person chosen at random was born
NikAS [45]

Answer:

0.2773 = 27.73% probability that at the May celebration, exactly two members of the group have May birthdays

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they have a birthday in May, or they do not. The probability of a person having a birthday in May is independent of any other person. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Probability of a person being in May:

May has 31 days in a year of 365. So

p = \frac{31}{365} = 0.0849

Group of 20 friends:

This means that n = 20

What is the probability that at the May celebration, exactly two members of the group have May birthdays?

This is P(X = 2).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{20,2}.(0.0849)^{2}.(0.9151)^{18} = 0.2773

0.2773 = 27.73% probability that at the May celebration, exactly two members of the group have May birthdays

3 0
3 years ago
What is 105,159 round to the nearest ten thousand is
viva [34]
105,000 would be the correct answer to your problem.
3 0
3 years ago
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