I asked a question a while ago and nobody has answered it pls help

the recipe for pumpking pie instructs you to bake the pie at 425∘F, for 15 minutes and then reduce the oven temperature to 350∘F

lakkis [162]

Answer:

ΔT = -75°F

Step-by-step explanation:

ΔT = T₁ - T₀ = 350 - 425 = -75°F

4 0

3 years ago

What is the volume of a square based pyramid with a side 11 cm and a perpendicular height of 20 cm

Kaylis [27]

V=lw*h/3

So since its a square l and w are the same

11*11 = 121

h=20

20/3= 6.6666666

V=121*6.6666666

V= 806.66667

3 0

3 years ago

What is the probability that a randomly selected person is on the swim team? Express the probability as a percent rounded to the

frez [133]

<span>What is the probability that a randomly selected person is on the swim team?
28 out of 67 people are on the swim team
so that's 28/67
</span><span>41.7910448% round to the nearest tenth
41.8% is the answer.

Hope this helps, Have a nice day!</span>

5 0

3 years ago

In a class of 147 students, 95 are taking math (M), 73 are taking science (S), and 52 are taking both math and science. What is

Marina86 [1]

95/294 orrr 0.3231 And you just round that to the nearest 10th

5 0

3 years ago

A common way for two people to settle a frivolous dispute is to play a game of rock-paper-scissors. In this game, each person si

Leokris [45]

Answer:

(a) P(A) = 0.34

(b) P(B) = 0.33

(c) P(C) = 0.33

(d) The Complement of event A = 1 - P(A) = 0.66

Step-by-step explanation:

We are given that in the long run, roommate A chooses rock 36% of the time, and roommate B chooses rock 22% of the time; roommate A selects paper 32% of the time, and roommate B selects paper 25% of the time; roommate A chooses scissors 32% of the time, and roommate B chooses scissors 53% of the time.

Let the probability that roommate A chooses rock = P( $R_A$ ) = 0.36

The probability that roommate A chooses paper = P( $P_A$ ) = 0.32

The probability that roommate A chooses scissors = P( $S_A$ ) = 0.32

The probability that roommate B chooses rock = P( $R_B$ ) = 0.22

The probability that roommate B chooses paper = P( $P_B$ ) = 0.25

The probability that roommate B chooses scissors = P( $S_B$ ) = 0.53

(a) Let A = event that roommate A wins the game and thus does not have to wash the dishes.

This will happen only when roommate A chooses rock and roommate B chooses scissors or roommate A chooses paper and roommate B chooses rock or roommate A chooses scissors and roommate B chooses paper.

So, P(A) = $P(R_A) \times P(S_B) + P(P_A) \times P(R_B) + P(S_A) \times P(P_B)$

= (0.36 $\times$ 0.53) + (0.32 $\times$ 0.22) + (0.32 $\times$ 0.25)

= 0.1908 + 0.0704 + 0.08

P(A) = 0.34

(b) Let B = event that roommate B wins the game and thus does not have to wash the dishes.

This will happen only when roommate B chooses rock and roommate A chooses scissors or roommate B chooses paper and roommate A chooses rock or roommate B chooses scissors and roommate A chooses paper.

So, P(B) = $P(R_B) \times P(S_A) + P(P_B) \times P(R_A) + P(S_B) \times P(P_A)$

= (0.22 $\times$ 0.32) + (0.25 $\times$ 0.36) + (0.53 $\times$ 0.32)

= 0.0704 + 0.09 + 0.1696

P(B) = 0.33

(c) Let C = event that the game ends in a tie.

This will happen only when roommate A chooses rock and roommate B also chooses rock or roommate A chooses paper and roommate B also chooses paper or roommate A chooses scissors and roommate B also chooses scissors.

So, P(C) = $P(R_A) \times P(R_B) + P(P_A) \times P(P_B) + P(S_A) \times P(S_B)$

= (0.36 $\times$ 0.22) + (0.32 $\times$ 0.25) + (0.32 $\times$ 0.53)

= 0.0792 + 0.08 + 0.1696

P(C) = 0.3288 ≈ 0.33

(d) The complement of event A = P(A') = 1 - P(A)

= 1 - 0.34 = 0.66.

4 0

3 years ago