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Crazy boy [7]
3 years ago
6

Which equation is the inverse of y = 100 – x2?

Mathematics
2 answers:
yulyashka [42]3 years ago
7 0

Answer:

The function f be described by

The graph of this function, is the graph of the parent function , which is the parabola with vertex at (0, 0) which opes upwards:

i) reflected with respect to the y-axis, because of the minus

ii) shifted 100 units up

check the picture attached.

A function has an inverse only if it is decreasing or increasing.

So we must divide the following cases for which the inverses exist:

i)  with domain (-infinity, 0]

ii)  with domain [0, infinity)

To find the formula for the inverse function g of f, we use the property:

f(g(x))=x

thus,

so each of - and + cases, are the inverses of

i)  with domain (-infinity, 0]

ii)  with domain [0, infinity)

At this point, recall that the domain of a function, is the range of it's inverse function,

and the range of the function, is the domain of the inverse function.

thus,

the range of , which is [0,infinity) is the domain of

i)  with domain [0,infinity)

So our answer is:

inverse of i)  with domain (-infinity, 0] is

and the inverse of ii)  with domain [0, infinity) is

Step-by-step explanation:

aleksandr82 [10.1K]3 years ago
4 0
The function f be described by y=100- x^{2}

The graph of this function, is the graph of the parent function x^{2}, which is the parabola with vertex at (0, 0) which opes upwards:

i) reflected with respect to the y-axis, because of the minus

ii) shifted 100 units up

check the picture attached. 


A function has an inverse only if it is decreasing or increasing.


So we must divide the following cases for which the inverses exist:

i) y=100- x^{2} with domain (-infinity, 0]

ii) y=100- x^{2} with domain [0, infinity)


To find the formula for the inverse function g of f, we use the property:

f(g(x))=x

thus, 

f(g(x))=x\\\\ 100-[g(x)]^2=x\\\\g^2(x)=100-x\\\\g(x)= \mp\sqrt{100-x}



so each of - and + cases, are the inverses of 


i) y=100- x^{2} with domain (-infinity, 0]

ii) y=100- x^{2} with domain [0, infinity)


At this point, recall that the domain of a function, is the range of it's inverse function, 

and the range of the function, is the domain of the inverse function.

thus, 

the range of \sqrt{100-x}, which is [0,infinity) is the domain of 

i) y=100- x^{2} with domain [0,infinity)



So our answer is:

inverse of i) y=100- x^{2} with domain (-infinity, 0] is -\sqrt{100-x}


and the inverse of ii) y=100- x^{2} with domain [0, infinity) is 

\sqrt{100-x}

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The box plots below show student grades on the most recent exam compared to overall grades in the class: two box plots shown. Th
finlep [7]

Question:

The box plots below show student grades on the most recent exam compared to overall grades in the class: two box plots shown. The top one is labeled Class. Minimum at 70, Q1 at 74, median at 83, Q3 at 92, maximum at 100. The bottom box plot is labeled Exam. Minimum at 60, Q1 at 81, median at 87, Q3 at 91, maximum at 95. Which of the following best describes the information about the medians? (1 point) Group of answer choices

•The exam outlier at 60 makes the IQR narrower and the median higher.

•The class data is more evenly spread, which pulls its median down.

•The class median is lower than the exam median.

•The class Q3 is higher than the exam Q3.

Answer:

•The class Q3 is higher than the exam Q3.

Step-by-step explanation:

In the question we have two box plots

a) Box plots for class is given as

Minimum at 70, Q1 at 74, median at 83, Q3 at 92,

b) Box plots for exam is given as Minimum at 60, Q1 at 81, median at 87, Q3 at 91, maximum at 95.

When we compare the median of the class which is 83 and the median of the exam plots 87, we can see that the median of the exam is higher than the median of the class, hence the option

"•The class median is lower than the exam median". is wrong.

From the options given, the only correct option which best describes the information about the medians is

"•The class Q3 is higher than the exam Q3".

This is because when we compare the Q3 of the class which is 92 to the Q3 of the box which is 91 , we can see that the class Q3 is higher than the box Q3 hence the option is correct.

8 0
3 years ago
Evaluate the expression shown below and write your answer as a fraction in simplest form 1/9+1/12
netineya [11]
The answer would be 7/36.
8 0
3 years ago
Can someone please help me
Readme [11.4K]
Surface Area of the figure is 1208 square centimeters
a=20
b=13
c=12
d=5
e=8
Top face:
A1=a×e=20×8
ae=160
Bottom face:
A2(a+2d)×e=(20+2×5)×8=(20+10)×8=30×8
(a+2d)e=240
Front face:
Rectangle
a×c=20×12=240
Triangle:
12c×d=12×12×5=6×5=30
A3Rectangle +2 triangles
240+2×30=240+60=300
(a+d)c=300
Slant face:
A4=b×e=13×8=104
be=104
Total surface area
A=A1+A2+2(A3+A4)
A1=160
A2=240
A3=300
A4=104
Thus,
A=160+240+2(300+104)
A=400+2(404)
A=400+808=1208
Surface Area of the figure is 1208 square centimeters


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3 years ago
Solve the system using elimination
antoniya [11.8K]
Eliminate x's
multiply 2nd equation by -2 ad add to first

2x+3y=9
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0x-7y=-7

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divide by -7
y=1

sub back

2x+3y=9
2x+3(1)=9
2x+3=9
minus 3
2x=6
divide 2
x=3


x=3
y=1

(x,y)
(3,1)

D
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4 years ago
Use the graph or table to write a linear function that relates to y to x. I need help on answering number 8, please and thank yo
siniylev [52]

Answer: y = 2/1 x 0

Step-by-step explanation:

Y=mx+b

2 and 1 are the “rise and run” (m) (from one point to the next, you must go up 2 units then right 1 unit)

The y intercept (b) is the point where it is on the y axis but 0 on the x axis, so 0

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