Answer:
The land which are used for exhibits are <u>89 acres</u> (approximately).
Step-by-step explanation:
Given:
Village is spread across 240 acres of land. 37% of land is used for the exhibits.
Now, we have to find acres of land which are used for exhibits.
So, here it is given that land used for exhibits is 37%, and we have to calculate the quantity from the percentage given:
According to question:
37% of 240 acres of land.



So, the land used for exhibits are 88.80 acres.
Therefore, the land which are used for exhibits are <u>89 acres </u>(approximately).
Answer:
The answer is -15/20, -1/4, 7. Thanks
Answer:
L=36, W=12
Step-by-step explanation:
In the attached file
Answer:
y = 0.5 cosine (4 (x - pi/2)) - 2
Step-by-step explanation:
Taking the general form:
y = A cosine (Bx - Cπ)) + D
In the following case. the constants are:
y = 0.5 cosine (4x - 2π)) - 2
A: 0.5
B: 4
C: 2π
D: -2
The range of this function is:
range = [-|A|+D, |A|+D]
range = [-0.5-2, 0.5-2]
range = [-2.5, -1.5]
Which coincides with "It has a maximum at negative 1.5 and a minimum at negative 2.5"
At x = 0, the function value is:
y = 0.5 cosine (4(0) - 2π)) - 2
y = 0.5 - 2 = -1.5
As indicated in "a curve crosses the y-axis at y = negative 1.5"
The period of the function is:
period: 2π/B
period = 2π/4 = π/2 or 2 cycles at π
as described in "It goes through 2 cycles at pi."