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daser333 [38]
3 years ago
11

Free pts!! Have a great day!

Mathematics
1 answer:
alukav5142 [94]3 years ago
4 0

<em><u>Thanks !</u></em>

<em><u>Have a great day you too !! </u></em>

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F(x) = x2 + 1<br> g(x) = 5 – x
xz_007 [3.2K]

Answer:

g(x) = 5 – x

Step-by-step explanation:

7 0
3 years ago
Why is 6√3 irrational or rational?
Oduvanchick [21]

Answer:

irrational.

Step-by-step explanation:

√3 is irrational.

product of rational and irrational number is always irrational.

6×√3=6√3

6 0
2 years ago
Read 2 more answers
In the diagram, point C represents the center of the sphere. Diego says that the part of the sphere labeled D is the radius. Gre
Katen [24]

Answer:

Gregoire is correct; the diameter is a chord that passes through the center of the sphere.

Step-by-step explanation:

A sphere is a geometrical shape formed from a circle. Some of its parts are: diameter, center, radius circumference, etc.

The center of a sphere is a point at its middle. The diameter is a straight line, e.g a chord, that is drawn from one point on the circumference of a sphere to another point and passes through its center. While radius is a line that is from the center of the sphere to a point on its circumference.

A diameter is twice of a radius, so that:

                            Radius = \frac{Diameter}{2}

⇒                        Diameter = 2 × Radius

Therefore with respect to the question, Gregoire is correct because a diameter is a chord that passes through the center of the sphere.

3 0
3 years ago
Read 2 more answers
Someone please help me with this lol… have no idea what I’m doing
Sholpan [36]

Given:

\cos \theta =\dfrac{3}{5}

\sin \theta

To find:

The quadrant of the terminal side of \theta and find the value of \sin\theta.

Solution:

We know that,

In Quadrant I, all trigonometric ratios are positive.

In Quadrant II: Only sin and cosec are positive.

In Quadrant III: Only tan and cot are positive.

In Quadrant IV: Only cos and sec are positive.

It is given that,

\cos \theta =\dfrac{3}{5}

\sin \theta

Here cos is positive and sine is negative. So, \theta must be lies in Quadrant IV.

We know that,

\sin^2\theta +\cos^2\theta =1

\sin^2\theta=1-\cos^2\theta

\sin \theta=\pm \sqrt{1-\cos^2\theta}

It is only negative because \theta lies in Quadrant IV. So,

\sin \theta=-\sqrt{1-\cos^2\theta}

After substituting \cos \theta =\dfrac{3}{5}, we get

\sin \theta=-\sqrt{1-(\dfrac{3}{5})^2}

\sin \theta=-\sqrt{1-\dfrac{9}{25}}

\sin \theta=-\sqrt{\dfrac{25-9}{25}}

\sin \theta=-\sqrt{\dfrac{16}{25}}

\sin \theta=-\dfrac{4}{5}

Therefore, the correct option is B.

6 0
2 years ago
A professor grades students on four tests, a term paper, and a final examination. Each test counts as 15% of the course grade. T
alina1380 [7]

Answer:

The Alans's average for the course is 84.5

Step-by-step explanation:

We are given

There are 4 tests, A Term paper and a Final examination.

Score = 92, 78, 82, 90.

Term paper score = 80

Final examination score = 86

Weighted mean = ∑ w.f/∑w

     also the sum of all the weights is 100% = 1

weighted mean = 15%*92 + 15%*78+15%*82+15%*90+20%*80+20%*86/1

                         = 51.3 + 33.2

                         =  84.5

Therefore the Alans's average for the course is 84.5

5 0
2 years ago
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