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Anettt [7]
2 years ago
9

Which equations represent an indirect variation relationship whit a constant of variation equal to -4? Select ALL correct answer

s
A) xy = -4

b) y = -4/x

c) y = x/-4

d) y = -4x​
Mathematics
1 answer:
natali 33 [55]2 years ago
5 0

The equations that represent an indirect variation relationship with a constant of variation equal to -4 are y = -4/x and xy = -4

<h3>Direct and indirect variation</h3>

An indirect variation is also known as the inverse variation

If the variable y is indirectly proportional to x , this is expressed as:

y = k/x

where

k is the variation constant

If the variation constant is -4, then;

y = -4/x

Hence the equations that represent an indirect variation relationship with a constant of variation equal to -4 are y = -4/x and xy = -4

Learn more on variation here: brainly.com/question/5247042

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Which number lint represents the solution set for the inequity -1/2x&gt;4
g100num [7]

Answer:

B. x < -8

Step-by-step explanation:

Well first we need to get x by itself.

To do that we do 4 / -1/2 = -8

And since a negative was divided the > changes to a <.

So x<-8.

If x is less than -8 the line starts at -8 and goes to the left.

<em>Thus,</em>

<em>the answer is choice b.</em>

<em />

<em>Hope this helps :)</em>

5 0
3 years ago
Problem:<br><br> 3 divided 5= 3/5<br><br> ——— x ——— = ———
grin007 [14]

Answer:

3=1/5

Step-by-step explanation:

hope this helps :) have a nice day :)

3 0
3 years ago
a glacier receded 4 feet a day for a period of 25 days. how much shorter was the glacier at the end of the period.
dangina [55]

Alright, lets get started.

In the question given that glacier receded 4 feet a day for a period of 25 days.

Which shows in 1 day, it recedes = 4 feet

means in 1 day, the height of the glacier gets shorter = 4 feet

So, in 25 days, the height of the glacier gets shorter = 4 * 25

So, in 25 days, the height of the glacier gets shorter = 100 feet

It means the glacier will get 100 feet shorter at the end of the period of 25 days. : Answer

Hope it will help :)



6 0
3 years ago
Given a=20 and b=a/4-3 what is the value of b
xxTIMURxx [149]

Answer: b=20

Step-by-step explanation:

Subsitute a for 20.

b=20/4-3

b=20/1

b=20

5 0
3 years ago
Read 2 more answers
Given the function f(x) = x^4 + 3x^3 - 2x^2 - 6x - 1, use intermediate theorem to decide which of the following intervals contai
marta [7]

f(x) = x^4 + 3x^3 - 2x^2 - 6x - 1

Lets check with every option

(a) [-4,-3]

We plug in -4  for x  and -3 for x

f(-4) = (-4)^4 + 3(-4)^3 - 2(-4)^2 - 6(-4) - 1= 55

f(-3) = (-3)^4 + 3(-3)^3 - 2(-3)^2 - 6(-3) - 1= -1

f(-4) is positive and f(-3) is negative. there is some value at x=c on the interval [-4,-3] where f(c)=0. so there exists atleast one zero on this interval.

(b) [-3,-2]

We plug in -3  for x  and -2 for x

f(-3) = (-3)^4 + 3(-3)^3 - 2(-3)^2 - 6(-3) - 1= -1

f(-2) = (-2)^4 + 3(-2)^3 - 2(-2)^2 - 6(-2) - 1= -5

f(-2) is negative and f(-3) is negative. there is no value at x=c on the interval [-3,-2] where f(c)=0.  

(c) [-2,-1]

We plug in -2  for x  and -1 for x

f(-2) = (-2)^4 + 3(-2)^3 - 2(-2)^2 - 6(-2) - 1= -5

f(-1) = (-1)^4 + 3(-1)^3 - 2(-1)^2 - 6(-1) - 1= 1

f(-2) is negative and f(-1) is positive. there is some value at x=c on the interval [-2,-1] where f(c)=0. so there exists atleast one zero on this interval.

(d) [-1,0]

We plug in -1  for x  and 0 for x

f(-1) = (-1)^4 + 3(-1)^3 - 2(-1)^2 - 6(-1) - 1= 1

f(0) = (0)^4 + 3(0)^3 - 2(0)^2 - 6(0) - 1= -1

f(-1) is positive and f(0) is negative. there is some value at x=c on the interval [-1,0] where f(c)=0. so there exists atleast one zero on this interval.

(e) [0,1]

We plug in 0  for x  and 1 for x

f(0) = (0)^4 + 3(0)^3 - 2(0)^2 - 6(0) - 1= -1

f(1) = (1)^4 + 3(1)^3 - 2(1)^2 - 6(1) - 1= -5

f(0) is negative and f(1) is negative. there is no value at x=c on the interval [0,1] where f(c)=0.  

(f) [1,2]

We plug in 1  for x  and 2 for x

f(1) = (1)^4 + 3(1)^3 - 2(1)^2 - 6(1) - 1= -5

f(2) = (2)^4 + 3(2)^3 - 2(2)^2 - 6(2) - 1= 19

f(-4) is positive and f(-3) is negative. there is some value at x=c on the interval [-4,-3] where f(c)=0. so there exists atleast one zero on this interval.

so answers are (a) [-4,-3], (c) [-2,-1],  (d) [-1,0], (f) [1,2]

8 0
3 years ago
Read 2 more answers
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