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marissa [1.9K]
2 years ago
10

If the point (4,-2) is included in a direct variation relationship, which point also belongs in this direct variation?

SAT
1 answer:
pashok25 [27]2 years ago
4 0

Answer:there is a vgraph so where it says 4 at the bottom then go under to -2 then ur done.

Explanation:

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Suppose that y varies jointly with w and x and inversely with z and y=400.
Zarrin [17]

The equation which can be used to model the relationship is y = 8wx / z

<h3>How to write and solve proportional equation</h3>

y = (k × w × x) / z

where,

  • k = constant of proportionality

y = 400

w = 10

x = 25

z = 5

  • substitute into the equation

y = (k × w × x) / z

400 = (k × 10 × 25) / 5

400 = 250k / 5

  • cross product

2000 = 250k

k = 2000 / 250

k = 8

Therefore,

y = (k × w × x) / z

y = (8 × w × x) / z

y = 8wx / z

The complete question

Suppose that y varies jointly with w and x and inversely with z and y = 400 when w = 10, x = 25 and z = 5. How do you write the equation that models the relationship?

Learn more about variation:

brainly.com/question/6499629

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Answer:

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Explanation:

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Paul, colin and brian are waiters. One night the restaurant earns tips totalling £71. 10. They share the tips in the ratio 2:3:4
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At an ocean depth of 20 meters, a buoy bobs up and then down 2 meters from the ocean's depth. Four seconds pass from the time th
stiv31 [10]

The first and second coordinate points of the sine graph are;

(0, 20) and (2, 22)

<h3>Sine Graph expression</h3>

The general formula we will use to plot the graph is;

y = [Asin (2πx/t)] + ∅      (Note that sin is in radians)

where;

A is amplitude

t is period

∅ is phase shift

We are told that the buoy bobs up and then down 2 meters from the ocean's depth. This means that;

Amplitude; A = 2

Now, Four seconds pass from the time the buoy is at its highest point to when it is at its lowest point. Thus;

Period = 2 * 4 = 8 seconds

Assume at x = 0, the buoy is at normal ocean depth. Thus;

Phase shift; ∅ = 20

Thus, we have;

y = [2sin((2πx/8)] + 20  

At x = 0, we have;

y = [2sin((2π*0/8)] + 20  

y = 0 + 20

y = 20

Thus, first point is; (0, 20)

Since the second point must be a maximum or minimum value on the graph closest to the first point, then we put 2 for x to get the coordinate of the second point;

y = [2sin((2π*2/8)] + 20  

y = [2sin((2π*2/8)] + 20  

y = [2sin(π/2)] + 20  

In radians, sin(π/2) = 1. Thus;

y = (2 * 1) + 20

y = 22

Second point is (2, 22)

Using the first and second point coordinates, we will use sine tool to graph the function as attached below.

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