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3 years ago

5

In the figure, the dashed line divides the arrow in half. What is the total area of the arrow? 60 square centimeters 68 square c

entimeters 80 square centimeters 82 square centimeters NextReset

2 answers:

WARRIOR [948]3 years ago

6 0

Answer:

80 square centimeters

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The total area of the arrow is equal to the area of a rectangle plus the area of a triangle

step 1

Find out the area of the rectangle

The area of rectangle is equal to

$A_1=LW$

we have

$L=17\ cm\\W=4\ cm$

substitute

$A_1=(17)(4)=68\ cm^2$

step 2

Find the area of triangle

The area of triangle is equal to

$A_2=\frac{1}{2}(b)(h)$

we have

$b=4+2+2=8\ cm\\W=20-17=3\ cm$

substitute

$A_2=\frac{1}{2}(8)(3)=12\ cm^2$

step 3

The area of the arrow is equal to

$A=A_1+A_2$

substitute the values

$A=68+12=80\ cm^2$

Lina20 [59]3 years ago

5 0

Answer:

80 square centimeters

Step-by-step explanation:

i did it and got it right

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Brian needs to start planning for an upcoming move. He is choosing two different size boxes to pack the majority of his stuff. T

GenaCL600 [577]

Solution:

Given,

Volume of the-

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Second cube box=13824in³

We know that volume of cube =a³

So for the first box

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Now, surface area of the first box

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and for the second box

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3 years ago

What is the fully factored form of the expression 45x²y2 + 18x3

Llana [10]

Answer:

9x^2(5y^2 + 2x).

Step-by-step explanation:

First find the Greatest Common Factor of the 2 terms.

GCF of 18 and 45 = 9

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The complete GCF is therefore 9x^2.

So, dividing each term by the GCF, we obtain:

9x^2(5y^2 + 2x).

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3 years ago

Consider the following division of polynomials.

Bond [772]

$x^4=x^2\cdot x^2$ . Multiplying the denominator by $x^2$ gives

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Subtracting this from the numerator gives a remainder of

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$-x^3=-x\cdot x^2$ . Multiplying the denominator by $-x$ gives

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and subtracting this from the previous remainder gives a new remainder of

$(-x^3-x^2-6x+8)-(-x^3-2x^2-8x)=x^2+2x+8$

This last remainder is exactly the same as the denominator, so $x^2+2x+8$ divides through it exactly and leaves us with 1.

What we showed here is that

$\dfrac{x^4+x^3+7x^2-6x+8}{x^2+2x+8}=x^2-\dfrac{x^3+x^2+6x-8}{x^2+2x+8}$

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and this last expression is the quotient.

To verify this solution, we can simply multiply this by the original denominator:

$(x^2+2x+8)(x^2-x+1)=x^2(x^2-x+1)+2x(x^2-x+1)+8(x^2-x+1)$

$=(x^4-x^3+x^2)+(2x^3-2x^2+2x)+(8x^2-8x+8)$

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Step-by-step explanation:

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