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DiKsa [7]
2 years ago
7

You are the Emergency Management Director of a small island nation. Your nation has come under Cyber-attack and the attackers ha

ve made non-functional the Communications system (Phone, Internet, and Cellular), Water supply, Electrical, Natural Gas, and Waste Treatment. Your staff assures you that each system can be recovered but will take an undetermined time period. You must decide what system should be made operational first with the limited staff available to you.
Computers and Technology
1 answer:
kozerog [31]2 years ago
8 0

Answer:

okay actually what are you trying to get an answer for

Explanation:

You might be interested in
Write a function that reads from a file the name and the weight of each person in pounds and calculates the equivalent weight in
spayn [35]

Answer:

#include <iostream>

#include <fstream>

#include <iomanip>

using namespace std;

int main(){

   string name;

   double weightKg, weightPd;

   cout<< fixed << setprecision(2);

   fstream myFile("filename.txt");

   while (getline( myFlie, name, weightPd)){

       weightKg = weight * 0.453592;

       cout<< name << weightPd <<weightKg;

   }

   myFile.close();

}

Explanation:

The C++ source code reads in the content of a file that has a name and weight value in pounds and outputs the name, weight in pounds and the weight in kilograms.

3 0
3 years ago
What are the Database used in RDBMS and DBMS<br>please answer immediately​
frosja888 [35]

Answer:

The best example for the DBMS is certainly the Microsoft Access. And various examples of RDBMS are MySQL, Sql Server, Amazon DynamoDB and so on. However, its essential to understand the difference between the RDBMS and the DBMS. The main difference between the two is certainly that in the RDBMS the application stores the data in tabular manner, and DBMS the data is stored as files. In the RDBMS the tables comes with identifier known as primary key, and the data values are being saved in the form of tables.

Explanation:

Please check the answer section.

4 0
3 years ago
what is the molarity of a solution prepared by dissolving 15.0g of sodium hydroxide in enough water to make a total of 225 ml of
Reptile [31]

Answer:

1.6666 g/mol = 1 \frac{2}{3} g/mol

Explanation:

Molar mass of NaOH= 23+16+1 =40g/mol

Mols in 15g = 15/40 mol

If this was dissolved in 225ml of water molarity of the solution is

\frac{15}{40} ÷ 225 x 1000 = 1.6666 g/mol = 1 \frac{2}{3} g/mol

5 0
3 years ago
What do you mean by algorithm​
Snowcat [4.5K]

A process or set of rules to be followed in calculations or other problem-solving operations, especially by a computer.

7 0
3 years ago
Read 2 more answers
Assignment Background Video games have become an outlet for artists to express their creative ideas and imaginations and a great
Sphinxa [80]

Answer:

Code

import csv

def open_file():

try:

fname=input("Enter the filename to open (xxx.yyy): ")

fp=open(fname,encoding='utf-8')

return fp

except FileNotFoundError:

print("File not found! Please Enter correct filename with extension")

return open_file()

def read_file(fp):

fields = []

rows = []

csvreader = list(csv.reader(fp))

# skiped 1 row because it contains field name

fields = csvreader[0]

D1={}

D2={}

D3={}

# accessing the data of csv file

for line in csvreader[1:]:

name = line[0].lower().strip()

platform = line[1].lower().strip()

if line[2]!='N/A':

year = int(line[2])

else:

year=line[2]

genre = line[3].lower().strip()

publisher = line[4].lower().strip()

na_sales = float(line[5])

eur_sales = float(line[6])

jpn_sales = float(line[7])

other_sales = float(line[8])

global_sales=(na_sales+eur_sales+jpn_sales+other_sales)*1000000

if name not in D1:

D1[name]=[]

D1[name].append((name, platform, year, genre, publisher,global_sales))

if genre not in D2:

D2[genre]=[]

D2[genre].append((genre, year, na_sales, eur_sales,jpn_sales, other_sales, global_sales))

if publisher not in D3:

D3[publisher]=[]

D3[publisher].append((publisher, name, year, na_sales,eur_sales, jpn_sales, other_sales, global_sales))

# sorting

temp={}

# sorting keys

for Keys in sorted (D1) :

ls=D1[Keys]

ls=sorted(ls,key=lambda x: x[-1]) # sorting values

temp[Keys]=ls

D1=temp.copy()

temp={}

# sorting keys

for Keys in sorted (D2) :

ls=D2[Keys]

ls=sorted(ls,key=lambda x: x[-1]) # sorting values

temp[Keys]=ls

D2=temp.copy()

temp={}

# sorting keys

for Keys in sorted (D3) :

ls=D3[Keys]

ls=sorted(ls,key=lambda x: x[-1]) # sorting values

temp[Keys]=ls

D3=temp.copy()

return D1,D2,D3

 

def main():

fp=open_file()

D1,D2,D3=read_file(fp)

# displaying the row_count in dictionaries

cnt=0

for d in D1:

cnt+=1

print(cnt)

print("\n\n=============================================\n\n")

cnt=0

for d in D2:

cnt+=1

print(cnt)

print("\n\n=============================================\n\n")

cnt=0

for d in D3:

cnt+=1

print(cnt)

print("\n\n=============================================\n\n")

 

 

if __name__=="__main__":

main()

Explanation:

see code and see output attached

7 0
3 years ago
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