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Aleks [24]
3 years ago
9

Propon

Mathematics
1 answer:
hoa [83]3 years ago
7 0

Answer:

They are shown together to find units of 4 total

4 (j/ total + s/total )

= 4 (1/4 + 3/4)

=  4/4 + 12/4

= 4 cups total

Then show letters and work out for j + s

4(j/3 + 3/4) = 4

4j/3 + 12/4 = 4

4j/3 + 3 = 4

4j/3 = 4-3

4j/3= 1

j = 1/3     s = 3/4 * 4 = 3  

You would rearrange 4 within the brackets to find total

3 (1/3 + 4t) = 4

   1 + 12t = 4

         12t = 4-1

         12t = 3

             t = 12/3 of the total

            t = 4

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Answer:

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Step-by-step explanation:

When we have a solution expressed in Q mg/ml, the concentration is (Q/10)%.

For example, a solution of 3 mg/ml is a 3/10=0.3% concentration solution, a solution of 40 mg/ml is a 40/10=4% concentration solution.

<em>Why? </em>

Q mg/ml means that 1 ml of solution has Q mg of the drug or active component. So, 100 ml have 100*Q mg.

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If a solution has Q/10 grams in 100 ml, then it is a (Q/10)% concentration.

Now, we have 5 ml of a solution that contains tobramycin, 3 mg/ml (each ml has 3 mg of tobramycin).

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On the other hand, we have another solution S containing 40 mg/ml of tobramycin. This means that each ml of S contains 40 mg of tobramycin.

Let x be the amount of ml of S we have to add to our first 5 ml.

If 1 ml of S contains 40 mg of  tobramycin, x ml contain 40*x mg.

If we add this x ml to our first 5 ml, we have 5+x ml containing 15+40*x mg of  tobramycin.  

Now, cross-multiply to get how much tobramycin contains 1 ml of this new solution.

5+x ml ____contain____15+40*x mg of  tobramycin

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And we have

\large \frac{5+x}{1}=\frac{15+40x}{?}\Rightarrow ?=\frac{15+40x}{5+x}

as a result, we have a solution of  

\large \frac{15+40x}{5+x}\;mg/ml

We want to prepare a solution 0.5% in concentration.

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\large \frac{(15+40x)/(5+x)}{10}=0.5

solving for x

\large \frac{(15+40x)/(5+x)}{10}=0.5\Rightarrow \frac{15+40x}{5+x}=5\Rightarrow 15+40x=25+5x\Rightarrow\\\\\Rightarrow 40x-5x=25-15\Rightarrow 35x=10\Rightarrow x=10/35=2/7 \;ml

So, we have to add just 2/7 ml of the stronger solution.

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Step-by-step explanation:

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Step-by-step explanation:

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