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Bezzdna [24]
3 years ago
15

Program to count how many even and odd number are in the range from M to N using C++ programming language

Computers and Technology
1 answer:
NemiM [27]3 years ago
8 0

Answer:

#include<stdio.h>

#include <iostream>

using namespace std;

 

int main(){

   int number, min, max;

   cout << "Enter the minimum range: ";

   cin >> min;

  cout << "Enter the maximum range: ";

   cin >> max;

   cout << "Odd numbers in given range are: ";

   for(number = min; number <= max; number++)

        if(number % 2 !=0)

            cout << number<< " ";

   cout<< "Even numbers in given range are: ";

   for(number = min; number <= max; number++)

        if(number % 2 ==0)

            cout << number << " ";

 

   return 0;

}

Explanation:

First of all, we take declare two variables. one as the lowest number of the range and the other as the upper limit of the range (in this case: <em>min</em> and <em>max</em>). We declare another variable (<em>number</em>) and store in it the lowest number of the range (<em>min</em>). To check whether the number currently stored as the value of the variable (<em>number</em>) is even, we take in account the remainder of that number divided by 2. If the remainder does not equals 0, we print that number as odd. We again check the remainder by dividing the number by 2. If the remainder does equals 0, we print that number as even.

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Answer:

FALSE

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5 0
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You are attending to a neighbor who is unresponsive, not breathing normally, and pulseless. Your spouse has left to activate EMS
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Write a Java program in jGRASP that creates a 2D integer array of 5 rows and 20 columns, fills it with increasing integer values
Alex73 [517]

Answer:

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Explanation:

//create a new class  TestArray

public class TestArray {

//define main method

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  }

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 }

}

}

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