Question

Implement one array of the English alphabet (26 characters). a) Create a function, getLetters() to cast and generate the array. b) Create a function, printLetters() to output the array. c) Create a function, swap() for swapping character variables. d) Create a function, reverseLetters() uses a loop and the swap() to reverse all array elements. e) Call printLetters()to Output the updated array. Hint: Set a variable for the first and last indices. Swap those values. Gradually move the first/last pointers to the middle of the array, swapping as you go. When the middle is reached, the array will be reversed.

Answer 1

#include <fstream>

#include <iostream>

#include <iomanip>

#include <cstring>

#include <cstdlib>

using namespace std;

// Function Declarations

void display(char alphabets[],int MAX_SIZE);

void reverse(char alphabets[],int MAX_SIZE);

void swap(char &ch1,char &ch2);

int main() {

 //Declaring constant

const int MAX_SIZE=26;

 

//Declaring a char array

char alphabets[MAX_SIZE];

 

//Populating the array with alphabets

for(int i=0;i<MAX_SIZE;i++)

{

 alphabets[i]=(char)(65+i);

 }

 

 cout<<"Original: ";

 display(alphabets,MAX_SIZE);

 reverse(alphabets,MAX_SIZE);

 cout<<"Reversed: ";

 display(alphabets,MAX_SIZE);

 return 0;

}

//This function will display the array contents

void display(char alphabets[],int MAX_SIZE)

{

 for(int i=0;i<MAX_SIZE;i++)

 {

    cout<<alphabets[i]<<" ";

 }

 cout<<endl;

}

//This function will reverse the array elements

void reverse(char alphabets[],int MAX_SIZE)

{

 int first,last;

 first=0;

 last=MAX_SIZE-1;

 

 while(first<last)

 {

   

    swap(alphabets[first],alphabets[last]);

    first++;

    last--;

   

 }

}

void swap(char &ch1,char &ch2)

{

 char temp;

 temp=ch1;

 ch1=ch2;

 ch2=temp;