Answer:
what is the full question? 4 units left or right or?
The probability of randomly chosen tall and obese individuals is 0.30.
Firstly complete the given table and find the total of each row and column.
Tall Medium Short Total
Obese 18 28 14 60
Normal 20 51 28 99
Underweight 12 25 9 46
Total 50 104 51 205
We have to find P(Tall | Obese).
P(Tall | Obese) = P(Tall and Obese) / P(Obese)
Now, P(Tall and Obese) = 18 ÷ 205
And, P(Obese) = 60÷205
Substituting the above values,
P(Tall | Obese) = 18÷205/ 60÷205
P(Tall | Obese) = 18/60
P(Tall | Obese) = 0.30
Hence the probability of a tall and obese individual is 0.30.
To learn more about probability, visit: brainly.com/question/11234923
#SPJ9
Yuh so the answer is (-3,4)
Answer= 2/3
5 2/3= multiply 5x3=15, then 5x2=10 which makes the fraction: 10/15, simplify by finding the highest common denominator that divides 10 & 15 equally, which would be 5,
5 divided into 10 is 2. 5 devided into 15 is 3 which makes your answer, 2/3.
not 100%, but it makes sense to me...
Answer:
y = -5x-5
Step-by-step explanation:
