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shusha [124]
3 years ago
9

What is the expanded form of 709.104

Mathematics
1 answer:
andreev551 [17]3 years ago
5 0
700 + 9 + .1 + .04

Hope this helps that the answer
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If m∠ABD= 48 and m m∠DBC= 78 find m∠ABC
Verdich [7]

Answer:

126 all you have to do is take the two measurements and add them together

6 0
3 years ago
Simplify (10 + 3i)(5 − 2i).
Romashka [77]
The answer I think is D but use the app photo math very useful:)
6 0
2 years ago
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En el colegio se realizó una campaña para medir el grado de obesidad de la población estudiantil. En la escuela hay 1 430 alumno
Lemur [1.5K]

Answer:

1144 o 286

Step-by-step explanation:

Si pregunta por la cantidad de personas que se pesaron, la respuesta es (8/10) * (1430) = 8 * 143 = 1144.

Si desea saber cuántas personas no se pesaron, la respuesta es 1430* (2/10) = 286

7 0
3 years ago
Find two consecutive odd integers if twice the larger, increased by the smaller equals 37,
Alexxx [7]

Answer:

11 and 13

Step-by-step explanation:

the first (smaller) odd integer can be called x

the second (larger) odd integer can be called x+2

2(x+2)+x = 37

<em>[simplify . . .]</em>

2x+4+x = 37

3x+4 = 37

<em>[subtract 4 from each side]</em>

3x = 33

<em>[divide each side by 3; find smaller odd integer]</em>

x = 11

<em>[add 2 to find larger odd integer]</em>

x+2 = 13

6 0
2 years ago
In ΔABC, m∠B = m∠C. The angle bisector of ∠B meets AC at point H and the angle bisector of ∠C meets AB at point K. Prove that BH
solniwko [45]

Answer:

See explanation

Step-by-step explanation:

In ΔABC, m∠B = m∠C.

BH is angle B bisector, then by definition of angle bisector

∠CBH ≅ ∠HBK

m∠CBH = m∠HBK = 1/2m∠B

CK is angle C bisector, then by definition of angle bisector

∠BCK ≅ ∠KCH

m∠BCK = m∠KCH = 1/2m∠C

Since m∠B = m∠C, then

m∠CBH = m∠HBK = 1/2m∠B = 1/2m∠C = m∠BCK = m∠KCH   (*)

Consider triangles CBH and BCK. In these triangles,

  • ∠CBH ≅ ∠BCK (from equality (*));
  • ∠HCB ≅ ∠KBC, because m∠B = m∠C;
  • BC ≅CB by reflexive property.

So, triangles CBH and BCK are congruent by ASA postulate.

Congruent triangles have congruent corresponding sides, hence

BH ≅ CK.

5 0
3 years ago
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