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maria [59]
3 years ago
8

QuisifA= 3B= 4C= 2soA x B - Cis​

Mathematics
2 answers:
Oksanka [162]3 years ago
7 0

Answer:

if

A= 3

B= 4

C= 2

so

A x B - C

iis

3 x 4 - 2

=12 - 2

=10 ✓

slava [35]3 years ago
7 0

Answer:

if

A= 3

B= 4

C= 2

so

A x B - C

iis

3 x 4 - 2

=12 - 2

=10 ✓

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What is the number in the middle of -7 and 6
Anon25 [30]

Answer:

-0.5

Step-by-step explanation:

Use the average formula:

Sum of all numbers/Number of items

6 + (-7) / 2

= -1/2

So, the number in the middle of -7 and 6 is -0.5

6 0
3 years ago
Read 2 more answers
The cost of a video game can be modeled by the question C=5x-2. The number of games sold can be modeled by the equation N=8x+5.
insens350 [35]
5x - 2 = 8x + 5.
-2 = -5x + 8x + 5
-2 = 3x +5
-7 = 3x

-7/3 = -2.3
4 0
3 years ago
Mr. Lopez wrote the equation 32 g + 8 g minus 10 g = 150 on the board. Four students explained how to solve for g.
11111nata11111 [884]

Answer:

Willhem

Step-by-step explanation:

The given equation is

Step 1 : Add 32g and 8g.

Step 2: Subtract 10 from 40.

Step 3: Divide both sides by 30, find the value of g.

The value of g is 5.

Therefore, Wilhem is correct.

7 0
3 years ago
Read 2 more answers
A restaurant uses 8 1/4 pounds of carrots to make 6 carrots cakes . Frank wants to use the same recipe. How many pounds of carro
monitta
1 1/2 pounds

16 ounces = 1 pound

8 1/4 pounds = 132 ounces
132 ounces/ 6 cakes = 22
22 ounces = 1 1/2 pounds
4 0
3 years ago
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Which of the following is NOT a linear factor of the polynomial function?
Natalija [7]

Answer:

Among the four choices, (x + 5) is the only one that is not a linear factor of this polynomial function.

Step-by-step explanation:

Let a denote some constant. A linear factor of the form (x - a) is a factor of a polynomial f(x) if and only if f(a) = 0 (that is: replacing all x in the polynomial f(x) \! with the constant a\! would give this polynomial a value of 0.)

For example, in the second linear factor (x - 2), the value of the constant is a = 2. Verify that the value of f(2) is indeed 0. (In other words, replacing all x in the polynomial f(x) \! with the constant 2 should give this polynomial a value of 0\!.)

\begin{aligned}f(2) &= 2^3 - 5\times 2^2 - 4 \times 2 + 20 \\ &= 8 - 20 - 8 + 20 \\ &= 0 \end{aligned}.

Hence, (x - 2) is indeed a linear factor of polynomial f(x).

Similarly, it could be verified that (x - 5) and (x + 2) are also linear factors of this polynomial function.

Rewrite the first linear factor (x + 5) in the form (x - a) for some constant a: (x + 5) = (x - (-5)), where a = -5.

Calculate the value of f(5).

\begin{aligned}f(5) &= (-5)^3 - 5\times (-5)^2 - 4 \times (-5) + 20 \\ &= (-125) - 125 + 20 + 20 \\ &= -210\end{aligned}.

f(5) \ne 0 implies that (x - (-5)) (which is equivalent to (x + 5)) isn't a linear factor of this polynomial function.

3 0
3 years ago
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