For the given cost equation we have:
a) Fixed cost is $900.
b) For making 25 items the cost is $1150.
c) D: x ∈ [0, 150]
R: c ∈ [900, 2400]
<h3>
Working with the cost equation.</h3>
Here we know that the cost equation is:
c(x) = 10*x + 900.
First, we want to get the fixed cost, it is given by evaluating the function in x = 0.
c(0) = 10*0 + 900 = 900
The fixed cost is 900.
b) Now we want to get the cost for making 25 items, to get this, we just evaluate in x = 25.
c(25) = 10*25 + 900 = 250 + 900 = 1150
c) Now, if the maximum cost is 2400, then the maximum number of items that we can make is x₀, such that:
c( x₀) = 2400 = 10*x₀ + 900
Solving for x₀ we get:
x₀ = (2400 - 900)/10 = 150
Now we want to get the range and domain.
We know that we can make between 0 and 150 items, so the domain is:
D: x ∈ [0, 150]
For the range, we know that the fixed cost for 0 items is 900, and the maximum cost is 2400, then the range is:
R: c ∈ [900, 2400]
If you want to learn more about domain and range:
brainly.com/question/10197594
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</span> with b not equal to zero, so they are rational numbers.