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ryzh [129]
3 years ago
13

How do some of the flu symptoms actually help fight the flu?

Health
1 answer:
cricket20 [7]3 years ago
7 0

when your body heats up to like 100 degress thats your bodies way of fighting off the bacteria from the flu

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Which statement made by the patient with chronic obstructive pulmonary disease COPD indicates a need for further teaching regard
algol13

Answer:

"If my breathing gets worse, I should keep taking extra puffs of the inhaler until i can breathe more easily"

Explanation:

For the patient to make this statement, it shows that he or she have no knowledge of the use of ipratropium inhaler. This inhaler is expected to be used twice daily or in worse cases 3 to 4 times a day. Hence, the patient taking extra puffs of the inhaler instead of carrying out several available steps capable of allowing patient breathe more easily simply shows a lack of knowledge.

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What is a health risk you have seen in
kupik [55]

Answer:

▪Too much intake of fats and oils.

This will increase the risk of high blood pressure, hardening of the arteries, heart attack and stroke.

▪My solution. Eat a balanced diet as many times as you can because its healthy. All food types (protein, carbohydrates.......) have effects if one of them is taken too much.

▪According to my research (google) it is healthy to take 2 to 3 teaspoons of oil per day ,this will mean that you have taken 1/2 a litre of oil per month.

Hope it helps.☆

7 0
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When a patient become angry or embarrassed that they are being asking for payment, what will you do to lessen their negative rea
castortr0y [4]
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8 0
3 years ago
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Which of the following BEST describes a body in equilibrium?
sukhopar [10]

\textsf {\large{\underline { \underline {SOLUTION:-}}}}

⇰Let O be the point of observation on the ground OX.

⇰Let A and B be the two positions of the jet.

\bf➠Then, \angle XOA=60⁰ \: and   \: \angle \: XOB=30⁰ \\  \\

\bf ➠Draw \:   AL \perp \: OX \: and  \: BM \perp \: OX \\  \\

\bf \:⇰ Let \: AL=BM=h \: meters. \\  \\

\bf \: ⇰ \: Speed \: of \: Jet  = 720 \: km/hr\\

\bf =  \huge( \small \: 720 \times  \frac{5}{18}  \huge) \small \: m / s\\

\bf = 200 \: m/s

\bf \:➥ Time  \: taken \: to \: cover \: the \: distance  \: AB=15  \: sec  \\  \\

\bf➥ Distance  \: covered =(speed×time) \\  \\

\:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  \:  \bf = (200 \times 15)m = 3000m \\  \\

\bf \therefore LM=AB=3000m \\  \\

{ \bf \: ⇰  \: Let \: OL} = x   \:  \bf m \\  \\

\bf➥From  \: right  \: \triangle OLA, \: we \: have: \\

\bf \frac{OL}{AL} =cot \: 60⁰= \frac{1}{ \sqrt{3} } \implies \frac{x}{h}  =  \frac{1}{ \sqrt{3} }  \\  \\

\bf \implies \: x =  \frac{h}{ \sqrt{3} }  \:  \:  \:  \:  \:  \:  \: ....(1) \\  \\

\bf \:➥ From  \: right  \: \triangle \: OMB,we \: have: \\

\bf\frac{OM}{BM} =cot30⁰= \sqrt{3}  \\  \\

\bf \implies \:  \frac{x + 3000}{h}  =  \sqrt{3}  \\  \\

\bf[ \boxed{➯OM=OL+LM=OL+AB=(x+3000)m  \: and \: BM=h \: m]}

\bf \implies \: x + 3000 =  \sqrt{3} h \\

\bf \implies \: x = ( \sqrt{3} h - 3000) \:  \:  \:  \:  \:  \: ....(2) \\

⇰ Equating the value of x from (1) and (2),we get;

\bf \:  \sqrt{3} h - 3000  =  \frac{h}{ \sqrt{3} }  \\  \\

\implies \bf \: 3h  - 3000 \sqrt{3}  = h \\

\bf \implies \: 2h = (3000 \times  \sqrt{3} ) = (3000 \times 1.762) \\

\bf \implies \: h = (3000 \times 0.866) = 2598  \\  \\

\bf \:➥ Hence \: ,the \: required  \: height \: is \: \boxed{ \boxed{ \bf2598 \: m.}} \\  \\

☆To View full answer drag your screen ⇰

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shusha [124]
Oh yeah I have to get a new look
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