Answer:
0 i guess
Step-by-step explanation:
Answer:
Step-by-step explanation:
<em>I assume that the </em><u><em>polygon</em></u><em> is made up of a </em><em>rectangle</em><em> and </em><em>two triangles. </em><em>Thus, the </em><em>area</em><em> of the </em><u><em>polygon</em></u><em> is the area of the </em><u><em>triangles</em></u><em> and the </em><u><em>rectangle.</em></u>
<em>≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡</em>
➡ 
➡ 
<em>≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡</em>
Answer:
The answer should be rectangle only.
Answer:
m∠1 is 49° and m∠3 is 49°
Step-by-step explanation:
In the given figure
∵ There are 2 parallel lines
∵ A transversal cuts them
∴ ∠4 and ∠8 are corresponding angles
→ Corresponding angles are equal in measures
∴ m∠4 = m∠8
∵ m∠8 = 131°
∴ m∠4 = 131°
∵ ∠1 and ∠4 formed a pair of linear angle
∵ The sum of the measures of the linear angles is 180°
∴ m∠1 + m∠4 = 180°
→ Substitute ∠4 by 131°
∴ m∠1 + 131° = 180°
→ Subtract 131 from both sides
∵ m∠1 + 131 - 131 = 180 - 131
∴ m∠1 = 49°
∵ ∠1 and ∠3 are vertically opposite angles
∴ m∠1 = m∠3
∵ m∠1 = 49°
∴ m∠3 = 49°
