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Naddik [55]
3 years ago
10

The sum of 8 and t please

Mathematics
1 answer:
Tanzania [10]3 years ago
7 0

Answer:

Um 8t I think, your answer isn't very descriptive but I still want to help you. But by what your asking it would most likely be 8t.

Step-by-step explanation:

Anyways have a nice day/night :)

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If y varies inversely as the square of x, and y = 1/8 when x = 1, find y when x = 5.
Kisachek [45]
Y = k / x² ( y varies inversely as the square of x ) 
y = 1/8 when x = 1:
1/8 = k / 1²
8 k = 1
k = 1/8
For x = 5:
y = 1/8  / 5² = 1/8 : 25 = 1/8 · 1/25 = 1/200
Answer: A ) 1/200


6 0
3 years ago
Solve the given equation. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to three decimal plac
worty [1.4K]
So here is the answer to the given equation above.
To find the answer, we can just factor this one. 
<span>(2sinθ+1)(sinθ−1)=0</span><span>sinθ = <span><span>−1/</span>2</span>→θ = <span>{<span><span><span>−π/</span>6 </span>+ 2kπ, <span><span>7π/</span>6 </span>+ 2kπ</span>}</span></span><span><span>sinθ=1→θ=<span>{<span><span>π/2 </span>+ 2kπ</span>}
Hope this answers your question. Let me know if you need more help next time. Have a great day!</span></span></span>
8 0
4 years ago
Read 2 more answers
What best describes the graph of y = -|x+1| - 5
kkurt [141]

Answer:

Last one

Step-by-step explanation:

The minus infrot makes it open Down

Its x-... So it - 1

The other number keeps the -

3 0
2 years ago
Would the answer be 12.5
Schach [20]
Yes, it would be 12.5.
5 0
3 years ago
PLEASE PLEASE ANSWER!
muminat

The area of the shaded region is $8(\pi \ -\sqrt{3})\ \text{cm}^2.

Solution:

Given radius = 4 cm

Diameter = 2 × 4 = 8 cm

Let us first find the area of the semi-circle.

Area of the semi-circle = \frac{1}{2}\times \pi r^2

                                      $=\frac{1}{2}\times \pi\times 4^2

                                      $=\frac{1}{2}\times \pi\times 16

Area of the semi-circle = $8\pi cm²

Angle in a semi-circle is always 90º.

∠C = 90°

So, ABC is a right angled triangle.

Using Pythagoras theorem, we can find base of the triangle.

AC^2+BC^2=AB^2

AC^2+4^2=8^2

AC^2=64-16

AC^2=48

AC=4\sqrt{3} cm

Base of the triangle ABC = 4\sqrt{3} cm

Height of the triangle = 4 cm

Area of the triangle ABC = \frac{1}{2}\times b \times h

                                          $=\frac{1}{2}\times 4\sqrt{3}  \times 4

Area of the triangle ABC =  8\sqrt{3} cm²

Area of the shaded region

                   = Area of the semi-circle – Area of the triangle ABC

                   = $8\pi \ \text{cm}^2-8\sqrt{3}\ \text{cm}^2

                   = $8(\pi \ -\sqrt{3})\ \text{cm}^2

Hence the area of the shaded region is $8(\pi \ -\sqrt{3})\ \text{cm}^2.

3 0
3 years ago
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