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nikitadnepr [17]
3 years ago
5

Is a three-digt whole number

Mathematics
1 answer:
Rudiy273 years ago
5 0

Answer:

693

Step-by-step explanation:

7*9*11*3=693

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What is the answer to this problem
otez555 [7]
3 1/4 = 13/4
2 3/4 = 11/4

13/4 - 11/4 = 2/4 = 1/2
8 0
3 years ago
Read 2 more answers
Am pls answer this sorry​
Komok [63]

Answer:

16. 1

17. 3

18. 1

19. 1

20. 1

Step-by-step explanation:

I'm sorry that I don't speak in Filipino but I can help fill in the blanks.

(In brackets is the English translation)

12 pulgada = 1 piye (12 inch is 1 foot)

1 yard = 3 piye (1 yard is 3 feet)

10 sentimetro = 1 desimetro (10 centimeters is 1 decimeter)

1000 metro = 1 kilometro (1000 meters is 1 kilometer)

10 millimetro = 1 sentimetro (10 millimeters is 1 centimeter)

3 0
3 years ago
The sum of the digits of a two-digit number is 5. If the number is multiplied by 3, the result is 42. Write and solve a system o
Elenna [48]
A two digit number has a tens digit and a ones digit.
Let's say x = tens digit and y = ones digit

"The sum of the digits is 5"
x + y = 5

The next phrase is "the number multiplied by 3 is 42" but we need to represent the number using the digits. So they need to be multiplied first by their place value and added together. [Example: 34 = 3(10) + 4(1)]

The number is: 10x + y
3(10x + y) = 42

The system of equations: (two equations for two unknowns)
x + y = 5
30x + 3y = 42

Then you can use substitution or elimination to combine and solve.
I'll use elimination, multiply the entire top equation by -3 and add the equations together. y will cancel out

-3x - 3y = -15
30x + 3y = 42
------------------
27x + 0 = 27
x = 1

then plug x = 1 into either equation to find y

1 + y = 5
y = 4

remember the x and y represent digits so the number xy is 14
6 0
3 years ago
Ill give brainliest i really need help on this
Sever21 [200]
I think the answer is

B.
8 0
2 years ago
.0417 DIVIDED 100 PLZ HELP (⊙_⊙)
nikklg [1K]

Answer: 0.000417

Hope this helps can u give me brainliest

Step-by-step explanation:

7 0
3 years ago
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