Find the equation of the circle that has a diameter with endpoint located at (-5,-3) and (-11,-3).
1 answer:
Check the picture below.
you can pretty much, without having to use the distance formula, see the diameter is 6 units long, thus the radius is half that or 3 then.
now, without having to use the midpoint formula, if we move from either endpoint inwards 3 units, we'll end up at the center, -5 -3, is just -8, so the center will be at -8, -3.
![\bf \textit{equation of a circle}\\\\ (x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2 \qquad center~~(\stackrel{-8}{{{ h}}},\stackrel{-3}{{{ k}}})\qquad \qquad radius=\stackrel{3}{{{ r}}} \\\\\\\ [x-(-8)]^2+[y-(-3)]^2=3^2\implies (x+8)^2+(y+3)^2=9](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bequation%20of%20a%20circle%7D%5C%5C%5C%5C%20%0A%28x-%7B%7B%20h%7D%7D%29%5E2%2B%28y-%7B%7B%20k%7D%7D%29%5E2%3D%7B%7B%20r%7D%7D%5E2%0A%5Cqquad%20%0Acenter~~%28%5Cstackrel%7B-8%7D%7B%7B%7B%20h%7D%7D%7D%2C%5Cstackrel%7B-3%7D%7B%7B%7B%20k%7D%7D%7D%29%5Cqquad%20%5Cqquad%20%0Aradius%3D%5Cstackrel%7B3%7D%7B%7B%7B%20r%7D%7D%7D%0A%5C%5C%5C%5C%5C%5C%5C%0A%5Bx-%28-8%29%5D%5E2%2B%5By-%28-3%29%5D%5E2%3D3%5E2%5Cimplies%20%28x%2B8%29%5E2%2B%28y%2B3%29%5E2%3D9)
you can pretty much, without having to use the distance formula, see the diameter is 6 units long, thus the radius is half that or 3 then.
now, without having to use the midpoint formula, if we move from either endpoint inwards 3 units, we'll end up at the center, -5 -3, is just -8, so the center will be at -8, -3.
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This question had the following choices:
<span>A) $223,884.91
B) $226,753.98
C) $229,679.66
D) $234,068.73</span>
I used the Online Balloon Payment Loan Calculator and got this amount $226,753.92. This is nearest to Choice B.
For manual computation, use this formula in the 2nd attachment.
<span>A) $223,884.91
B) $226,753.98
C) $229,679.66
D) $234,068.73</span>
I used the Online Balloon Payment Loan Calculator and got this amount $226,753.92. This is nearest to Choice B.
For manual computation, use this formula in the 2nd attachment.