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Goshia [24]
3 years ago
9

Please help! Brainliest

Mathematics
1 answer:
Mama L [17]3 years ago
6 0

1.301

Explanation:

Given:

\log_a5 \approx 0.699 and \log_a2 \approx 0.301

Note that from the properties of logarithms,

\log_a20 = \log_a(5×4)

\:\:\:\:\:\:\:\:\:\:= \log_a(5×2^2)

\:\:\:\:\:\:\:\:\:\:=\log_a5 + \log_a(2)^2

\:\:\:\:\:\:\:\:\:\:=\log_a5 + 2\log_a2

\:\:\:\:\:\:\:\:\:\:\approx 0.699 + 2(0.301)

\:\:\:\:\:\:\:\:\:\:= 1.301

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konstantin123 [22]
Answer: a) It will be a right triangle with a hypotenuse of 75 and a vertical leg that is 62. 
b) The length of the kite string is 75 (given in the problem). However, I believe you are looking for the distance from the spot on the ground beneath the kite to Janet. That is about 42.2 m.

To find the missing distance in the right triangle. You have to use the Pythagorean Theorem.  I set it up and solve it below.

a^2 + b^2 = c^2
x^2 + 62^2 = 75^2
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3 0
3 years ago
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Oksana_A [137]

Answer:

C

Step-by-step explanation:

The general rule for the quadratic function is

y=ax^2+bx+c

Use the data from the table:

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We get the system of three equations:

\left\{\begin{array}{l}2500a+50b+c=130\\ \\4900a+70b+c=130\\ \\8100a+90b+c=200\end{array}\right.

Subtract these equations:

\left\{\begin{array}{l}4900a+70b+c-2500a-50b-c=130-130\\ \\8100a+90b+c-2500a-50b-c=200-130\end{array}\right.\Rightarrow \left\{\begin{array}{l}2400a+20b=0\\ \\5600a+40b=70\end{array}\right.

From the first equation

b=-120a

Substitute it into the second equation:

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2500\cdot \dfrac{7}{80}+50\cdot (-10.5)+c=130\Rightarrow 218.75-525+c=130\\ \\c=130-218.75+525=436.25

The quadratic function is

y=\dfrac{7}{80}x^2-10.5x+436.25\\ \\y=0.0875x^2-10.5x+436.25

4 0
3 years ago
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arlik [135]


We need to write the following expression and solve for x:

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Step-by-step explanation:

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Assoli18 [71]

Answer:

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