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strojnjashka [21]
3 years ago
14

Multiply 3x7, Minus 12=

Mathematics
1 answer:
Nezavi [6.7K]3 years ago
6 0

Answer:

Your answer would be 9

Step-by-step explanation:

hope this helps

pls mak brainliest

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286 mi in 5 1/2 hours as a unit rate
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286 ÷ 5 1/2 hours = 286 ÷ 5.5 = 52 final answer
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Ms. Troy would like you to make a copy of an outfit that she owns and really likes—a sleeveless dress with a short-sleeve jacket
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I think it is 82 in a.
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4 years ago
Find the sum of -75 and 105​
GuDViN [60]

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30

Step-by-step explanation:

-75 + 105= 30

(Hope this helps can I pls have brainlist (crown) ☺️)

3 0
3 years ago
Read 2 more answers
Solve the following quadratic equation 6x^2-5x-4=0
jeka94

Answer:

=

−

±

2

−

4

√

2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}

x=2a−b±b2−4ac​​

Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.

6

2

−

5

−

4

=

0

6x^{2}-5x-4=0

6x2−5x−4=0

=

6

a={\color{#c92786}{6}}

a=6

=

−

5

b={\color{#e8710a}{-5}}

b=−5

=

−

4

c={\color{#129eaf}{-4}}

c=−4

=

−

(

−

5

)

±

(

−

5

)

2

−

4

⋅

6

(

−

4

)

√

2

⋅

6

Step-by-step explanation:

6 0
3 years ago
A company manufactures televisions. The average weight of the televisions is 5 pounds with a standard deviation of 0.1 pound. As
Semenov [28]

Answer:

0.2564\text{ pounds}

Step-by-step explanation:

The 90th percentile of a normally distributed curve occurs at 1.282 standard deviations. Similarly, the 10th percentile of a normally distributed curve occurs at -1.282 standard deviations.

To find the X percentile for the television weights, use the formula:

X=\mu +k\sigma, where \mu is the average of the set, k is some constant relevant to the percentile you're finding, and \sigma is one standard deviation.

As I mentioned previously, 90th percentile occurs at 1.282 standard deviations. The average of the set and one standard deviation is already given. Substitute \mu=5, k=1.282, and \sigma=0.1:

X=5+(1.282)(0.1)=5.1282

Therefore, the 90th percentile weight is 5.1282 pounds.

Repeat the process for calculating the 10th percentile weight:

X=5+(-1.282)(0.1)=4.8718

The difference between these two weights is 5.1282-4.8718=\boxed{0.2564\text{ pounds}}.

8 0
3 years ago
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