P(B) = 1 - P(B') = 1 - (7/12) = 5/12
<span>P(A∩B)=<span><span>P(A∩<span>B′</span>)/</span><span>P(<span>B′</span>) </span></span>× <span><span>P(B)/</span>1
</span></span>Plugging values into the last equation we get:
<span>P(A∩B)=<span><span>1×12×5 / </span><span>6×7×12 </span></span>= <span>542</span></span>
Now we can make use of the following formula
<span>P(A|B)=<span><span>P(A∩B) / </span><span>P(B)</span></span></span><span>
by plugging in the values that we have found.
</span>
<span>5/42 is the numerator and the denominator is 5/12.
</span>
The bottom (denominator) is P(B) which equals 5/12.
<span>P(A|B)=<span><span>5×12 / </span><span>42×5 = 6/210
6/210 = 2/7
</span></span></span><span>p(a[b]) = 2/7</span>
Answer:
a process where green plants and some other organisms use sunlight to synthesize foods from carbon dioxide and water
Explanation:
hope this helps
1.No 2.yes 3.yes 4.no 5.no
C) Natural selection
When something happens in nature and something changes all of a sudden, the animals tend to adapt to what gives them more chances of survival. As a result, a large amount of the population would attempt to adapt in a way that helps them survive.
To solve this problem on genetic dominance, we will need a punnet square.
Let's let P represent purple-flowered and p represent white-flowered.
We have one purple flowered plant with the alleles PP, and we have one white flowered plant with the alleles pp. Using a punnet square, we can determine the alleles of the offspring.
<u>P</u> <u>P</u>
p| Pp Pp
p | Pp Pp
As we can tell from our punnet square, all of our offspring will have purple flowers. This is because the purple-flower allele is dominant and the white-flowered allele is recessive.
Since each flower has a dominant and recessive allele, they are heterozygous.
Therefore, the solution to this problem is D.
