Please help with this math problem ASAP! It is due tonight! Will give brainliest! :)

Mathematics

1 answer:

frosja888 [35]2 years ago

8 0

Answer:

sin(x) = $\frac{7}{25}$

x = 16.26°

Step-by-step explanation:

First use Pythagorean theorem to find the length of the hypotenuse. Use $a^2 + b^2 = c^2$ . Since we know a and b we can plug in to find c. When we plug in we get: $(7)^2 + (24)^2 = c^2$ . When we solve this out we get 25 = c.

Now that we know the value of c, we also know sin(x) = $\frac{opposite}{hypotenuse}$ . Using this we see that sin(x) = $\frac{7}{25}$ .

To get the exact degree value of x, take the inverse sin of $\frac{7}{25}$ :

$sin^-1(\frac{7}{25})$ which gives us 16.26020° rounded to 16.26°

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Which equation is the inverse of y = 100 – x2?<br> A.y= +or- sqrt 100-x A. is the correct answer

GREYUIT [131]

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2 years ago

Convert 1 cal/(m^2 * sec * °C) into BTU/(ft^2 * hr * °F)

Crazy boy [7]

Answer:

$1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

Step-by-step explanation:

To find : Convert $1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}$ into $\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

Solution :

We convert units one by one,

$1\text{ m}^2=10.7639\text{ ft}^2$

$1\text{ sec}=\frac{1}{3600}\text{ hour}$

$1\text{ cal}=0.003968\text{ BTU}$

Converting temperature unit,

$^\circ C\times \frac{9}{5}+32=^\circ F$

$1^\circ C\times \frac{9}{5}+32=33.8^\circ F$

So, $1^\circ C=33.8^\circ F$

Substitute all the values in the unit conversion,

$1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{10.7639\times \frac{1}{3600}\times 33.8}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$