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defon
2 years ago
11

Is 21/2:3 and 16:6 equivalent

Mathematics
1 answer:
Minchanka [31]2 years ago
6 0
Answer
21/2:3 and 16:6 are not equivalent
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If you spend 5 hours a week studying for English and 4.5 hours studying for math what is the ratio of time spent in math to stud
Vesna [10]

I think it would be 4.5:5  

:/ hope this might of helped

lol might have done it wrong tho

5 0
3 years ago
Determine what type of observational study is described. Explain. Researchers wanted to determine whether there was an associati
34kurt

Answer:

B. The observational study is a cross-sectional study because information is collected at a specific point in time.

Step-by-step explanation:

1) There are three types of Observational Studies: Case-control, cross-sectional and Cohort.

2) Since the researchers collected information from those 1800 adults at a certain time, then we can call it a cross-sectional study. It does not provide solid results since the research was not done over a period to collect further information. We don't know, for example, much more than what that association deeply mean.

3) If we wonder more, then the researchers would have to track those adults over a given period, i.e. a Cohort would be necessary.

4) Moreover, it's not "retrospective" for virtually every question, always makes us look back somehow, and it does not categorize a kind of observational study.

6 0
3 years ago
A rectangle has a height of 5y; and a width of 3y3 – 8y2 + 2y.
Korvikt [17]
Area= 15y^4-40y^3+10y^2

4 0
3 years ago
The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typo
muminat

Answer:

The required probability is 0.55404.

Step-by-step explanation:

Consider the provided information.

The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.

Average error for 7 pages booklet and 5 pages booklet series is:

λ = 0.2×7 + 0.3×5 = 2.9

According to Poisson distribution: {\displaystyle P(k{\text{ events in interval}})={\frac {\lambda ^{k}e^{-\lambda }}{k!}}}

Where \lambda is average number of events.

The probability of more than 2 typographical errors in the two booklets in total is:

P(k > 2)= 1 - {P(k = 0) + P(k = 1) + P(k = 2)}

Substitute the respective values in the above formula.

P(k > 2)= 1 - ({\frac {2.9 ^{0}e^{-2.9}}{0!}} + \frac {2.9 ^{1}e^{-2.9}}{1!}} + \frac {2.9 ^{2}e^{-2.9}}{2!}})

P(k > 2)= 1 - (0.44596)

P(k > 2)=0.55404

Hence, the required probability is 0.55404.

4 0
3 years ago
If a seamstress is paid 7.85 per hour and works 18.75 hours in one week how much is she paid for that week
umka21 [38]
$18.75 hours at $7.85 pet hour is exactly 1471875, moving the decimal 4 places to the left and round to the nearest penny is
$147.1875 Or $147.19
4 0
3 years ago
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