All categories

2 years ago

HELP! LAST ONE, I PROMISE, PLS!

Mathematics

1 answer:

madreJ [45]2 years ago

7 0

Answer:

the formula will be b = 3 think I'm pretty sure that will be there correct answer

You might be interested in

Find the area of the regular 15-gon with radius 10mm.

Nady [450]

318.83484250503 mm^2

6 0

3 years ago

A stone is thrown straight up from earth with D(t)= -4.9 t^2 + vt where D = height in meters, t= time in seconds, and v= initial

Vedmedyk [2.9K]

Answer:

(a) D(t)= -4.9 t^2 + vt

(b) 10 sec

(d) At t= 4sec, v= 9.8m/s (upwards) and at t= 9sec, v= 39.2m/s (downwards)

(e) -24.5m

(f) -49m/s (i.e. downwards)

(g) 0

Step-by-step explanation:

(b) Time in the air = 2v/g = 10sec

(d) Velocity at any time t = v -9.8t

So, at t= 4sec, velocity = 49 – 9.8(4) =9.8m/s

at t= 9sec, velocity = 49 – 9.8(9) = -39.2m/s

(e) Average velocity = $\frac{\int\limits^9_4 {v-9.8t} \, dt }{\int\limits^9_4 {1} \, dt }$ = -24.5m

(g) the stone is thrown vertically upwards, so no horizontal distance covered.

7 0

3 years ago

Which expression is equivalent to −1/ 12x−1 /3?

alexandr402 [8]

Answer:

$\frac{1}{12} (-x-4)$

Step-by-step explanation:

the expression we have is:

$-\frac{1}{12} x-\frac{1}{3}$

To find an equivalent expression, it would be helpful to express 1/3 so that it has a 12 in the denominator:

$\frac{1}{3}=\frac{4}{12}$

so we substitute this:

$-\frac{1}{12} x-\frac{4}{12}$

and now we have 1/12 in both terms :

$-\frac{1}{12}x-\frac{1*4}{12}$

so we can factor it (we take it out of each term: in the first we are left with -x and in the second with -4):

$\frac{1}{12} (-x-4)$

the equivalent expression is: $\frac{1}{12} (-x-4)$

5 0

4 years ago

2.5 miles is equivalent to 4km

rosijanka [135]

That is not true it is false

8 0

4 years ago

Ken's landscape gardening business creates odd-shaped lawns that include semicircles. Find the area of this semicircular section

salantis [7]

Answer:

Area of semicircular lawn is 9.82 square meter.

Step-by-step explanation:

Given:

Diameter of the semicircle = 5 m

So we will find the radius.

Radius is half of the diameter.

Radius $r=\frac{5}{2}=2.5\ m$

We need to find the area of the lawn.

Solution:

Now we know that;

Area of semicircle is half times π times square of the radius.

framing in equation form we get;

Area of semicircular lawn = $\frac12\pi r^2=\frac12\times\frac{22}{7}\times 2.5\times 2.5=9.82\ m^2$

Hence Area of semicircular lawn is 9.82 square meter.

7 0

3 years ago