What is the greatest common factor of 20x and 35y?

1 answer:

6 0

_______________________________________________________
The greatest common factor (GCF) of "20x and 35y" is: " 5 " .
_______________________________________________________
The answer is: " 5 " .
_______________________________________________________

Consider: "20x" and "35y" ;

Each of the TWO (2) terms contains "ONE" (1) [single] variable. The variable within EACH term differs from each other.

As such: "The greatest common factor (GCF) of "20x" and "35y" is the:
"greatest common factor (GCF) of "20" and "35" ;
_______________________________________________________
List the factors for each number:
_______________________________________________________
20: 1, 2, 4, 5, 10, 20 .

35: 1, 5, 7 , 35.
_______________________________________________________
The greatest common factor (GCF) of "20x and 35y" is: " 5 " .
_______________________________________________________
The answer is: " 5 " .
_______________________________________________________

You might be interested in

Simplify. logv7 13 + logv7 10 v=base exponent

Luda [366]

Bfukbcfjm jejejand keke a snow d chaka disks

4 0

3 years ago

Joe is a waiter at a local pizza parlor. he usually gets a tip from the tables he waits on. the bill for one table comes to $34

MAXImum [283]

T=34xP

T= tip for him
P= percent he charges for tip

6 0

3 years ago

A triangle with sides 11m , 13m and 18m is a right triangle. A True B False

Julli [10]

$\bold{\huge{\pink{\underline{ Solution}}}}$

$\bold{\underline{ Given :-}}$

A triangle with sides 11m, 13m and 18m

$\bold{\underline{ To \: Find :-}}$

We have to check it whether it is right angled triangle or not?

$\bold{\underline{ Let's \: Begin :-}}$

$\sf{\red{ In \:right \:angled\ : triangle, }}$

According to the Pythagoras theorem, The sum of the squares of perpendicular height and the square of the base of the triangle is equal to the square of hypotenuse that is sum of the squares of two small sides equal to the square of longest side of the triangle.

We imply it in the given triangle ,

$\sf{\red{ ( Perpendicular)² + (Base)² = (Hypotenuse)²}}$