You are to graph <span>y = |1.6x – 2| – 3.2. I trust you know that the graph of y=|x| is v-shaped, opening up, with vertex at (0,0).
Let's rewrite </span><span>y = |1.6x – 2| – 3.2 by factoring 1.6 out of |1.6x - 2|:
</span><span>y = 1.6*|x – 2/1.6| – 3.2
This tells us that the vertex of </span><span>y = |1.6x – 2| – 3.2 is at (2/1.6, -3.2). If you need an explanation of why this is, please ask.
Plot the vertex at (1.25, -3.2).
Find the y-intercept: Let x = 0 in </span><span>y = |1.6x – 2| – 3.2 and find y:
y = 2-3.2 = -1.2
The y-intercept is located at 0, -1.2)
Plot this y-intercept.
Now draw a straight line from the vertex to this y-intercept. Reflect that line across the y-axis to obtain the other half of the graph.</span>
Answer:
5.
x + 2(x + 1) = 8 --> x = 2
y = 2 + 1 = 3
7.
3(9 + 2y) + 5y = 20 --> y = -7/11
x = 9 + 2(-7/11) = 85/11
9.
3(-1 - 2y) + 5y = -1 --> y = -2
x = -1 - 2(-2) = 3
Answer:
X= 2 and y = 3
Step-by-step explanation:
An outlier<span> is an observation that lies an abnormal distance from other values in a random sample from a population. In a sense, this definition leaves it up to the analyst (or a consensus process) to decide what will be considered abnormal. Before abnormal observations can be singled out, it is necessary to characterize normal observations.
Basically the ones that are far away from the others.
Thus, the outliers for this graph are K and F
</span>
Answer:
M= -7
Step-by-step explanation:
M+9=2
M =2-9
M=-7
