Using the law os cosines formula b^2 = a^2 + c^2 - 2*a*c*cos(B)
a = 17, b = 8, c = 16
8^2 = 17^2 + 16^2 - 2*17*16* cos(B)
64 = 289 + 256 - 544 * cos(B)
544*cos(B) = 289 + 256 - 64
544 * cos(B) = 481
cos (B) = 481/544
B = arccos(481/544)
B = 27.8 degrees
Answer: no
Step-by-step explanation: the ratio 3:5 can be written as 3/5 which 3/5 is not equal to 4/6 or 7:9
Answer:
28 square centimeters
Step-by-step explanation:
The area of a trapezoid (formula):
(a + b) ÷ 2 x h
Where a & b are the bases, and h is height.
Use formula with given measurements:
(9 + 5) ÷ 2 x 4 = 28
Area is measured in square centimeters
(centimeters in this case)
Therefore the area if the trapezoid is 28 cm^2
I really hope this helps!
Answer:
5x - 2y = - 2
Step-by-step explanation:
Given the 2 equations
- 2x + y = 0 → (1)
- 7x + 3y = 2 → (2)
Subtracting (2) from (1) term by term
- 2x - (- 7x) + y - 3y = 0 - 2, that is
- 2x + 7x - 2y = - 2
5x - 2y = - 2
We use 2 different rules here:
1) sum of angles in a triangle is equal to 180 degrees
2) when a triangle side is a diameter of the circle, then angle opposite to diameter is equal to 90 degrees.
so from 2) we know that B= 90
then from first one:
sum of angles = 180 = 90 + (3x + 6) + x = 96 + 4x
so 180 - 96 = 4x
so x = 84/4
x = 21
so answer is
A= 3x+ 6 = 63 + 6 = 69
B = 90
C = 21
