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3 years ago

What is the sequence? 1,8,27,64,125

Mathematics

1 answer:

Marat540 [252]3 years ago

5 0

1^3 = 1 x 1 x 1 = 1
2^3 = 2 x 2 x 2 = 8
3^3 = 3 x 3 x 3 = 27
4^3 = 4 x 4 x 4 = 64
5^3 = 5 x 5 x 5 = 125

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The exponential function f(x) has a horizontal asymptote at y = 3. What is the

fenix001 [56]

Answer:

The function diverges to $+\infty$ .

Step-by-step explanation:

The function diverges to $+\infty$ .

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3 years ago

In the star below, all of the inscribed angles are congruent. Find the measure of each inscribed angle.

ozzi

Answer:

36 degrees for each angle.

Step-by-step explanation:

If you divide 180 by 5 (for each point in the star) you get 36 degrees.

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2 years ago

Need an explanation and answer for -25/28 ÷ (5/4)

lyudmila [28]

Answer:

-5/7

Step-by-step explanation:

When you divide fractions, you flip the second fraction, then multiply.

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3 years ago

Coach Evans recorded the height, in inches of each player on his team. The results are shown.

marysya [2.9K]

Answer:

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile $(Q_1)$

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile $(Q_3)$

Terms in arranged in ascending order:

$57,60,60,61,62,62,63,63,64$

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

$Q_1$ is median of terms $57,60,60,61$

Number of terms (n) = 4

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60$

So, $Q_1=60$

So, 25% of the heights of a team is less than 60 inches

$Q_3$ is the median of terms $62,63,63,64$

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63$

So, $Q_3=63$

So, 75% of the heights of a team is less than 63 inches

Interquartile range = $Q_3-Q_1=63-60=3$

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

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3 years ago

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katen-ka-za [31]

8x²+3y²=24

8x²+3y²-24=0

Let x be 1 ,

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Take different values of x &y and plot a graph!!!

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3 years ago