All categories

2 years ago

N(p)=4 means that there a four elements in a set P. Given:

Mathematics

1 answer:

viktelen [127]2 years ago

6 0

Answer:

n(20*u*40=50

Step-by-step explanation:

You might be interested in

Coefficient of x^2 in expansion of (x+2)^5

iVinArrow [24]

The x² term will be C(5,2)x²·2³ = 80x².

The coefficient is 80.

_____
C(n, k) = n!/(k!·(n-k)!)
C(5, 2) = 5·4/(2·1) = 10

8 0

3 years ago

WHOEVER ANSWERS IT WILL GET BRAINIST ASAP DUE IN 5 MINUTES

sweet-ann [11.9K]

Answer:

A. & B.

Step-by-step explanation:

General form is ax2 + bx + c = 0.

Must contain an x2 term

Must NOT contain terms with degrees higher than x2 eg. x3, x4 etc

5 0

3 years ago

Read 2 more answers

Lynne was making cookies and she

fomenos

Answer:

11/2is the answer hope it helps

8 0

3 years ago

Given R (7,-1), A (3,-6), B(-3,-6), E (-5,4), plot the points and trace the figure.

RUDIKE [14]

Answer:

See below

Step-by-step explanation:

Given R (7,-1), A (3,-6), B(-3,-6), E (-5,4)

Points plotted and they form a quadrilateral

See attached

4 0

3 years ago

The following six independent length measurements were made (in feet) for a line: 736.352, 736.363, 736.375, 736.324, 736.358, a

horrorfan [7]

Answer:

Assuming population data

$\sigma = \sqrt{0.000354}=0.0188$

Assuming sample data

$s = \sqrt{0.000425}=0.0206$

Step-by-step explanation:

For this case we have the following data given:

736.352, 736.363, 736.375, 736.324, 736.358, and 736.383.

The first step in order to calculate the standard deviation is calculate the mean.

Assuming population data

$\mu = \frac{\sum_{i=1}^6 X_i}{6}$

The value for the mean would be:

$\mu = \frac{736.352+736.363+736.375+736.324+736.358+736.383}{6}=736.359$

And the population variance would be given by:

$\sigma^2 = \frac{\sum_{i=1}^6 (x_i-\bar x)}{6}$

And we got $\sigma^2 =0.000354$

And the deviation would be just the square root of the variance:

$\sigma = \sqrt{0.000354}=0.0188$

Assuming sample data

$\bar X = \frac{\sum_{i=1}^6 X_i}{6}$

The value for the mean would be:

$\bar X = \frac{736.352+736.363+736.375+736.324+736.358+736.383}{6}=736.359$

And the population variance would be given by:

$s^2 = \frac{\sum_{i=1}^6 (x_i-\bar x)}{6-1}$

And we got $s^2 =0.000425$

And the deviation would be just the square root of the variance:

$s = \sqrt{0.000425}=0.0206$

6 0

3 years ago