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Elanso [62]
3 years ago
12

N(p)=4 means that there a four elements in a set P. Given:

Mathematics
1 answer:
viktelen [127]3 years ago
6 0

Answer:

n(20*u*40=50

Step-by-step explanation:

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There are 8 action, 3 comedy, and 5 drama DVDs on a shelf. Suppose three DVDs are selected at random from the shelf. Find each p
nordsb [41]
8 action, 3 comedy, 5 drama....total = 16 dvd's

P(2 action, then a comedy)...without replacement

8/16 * 7/15 * 3/14 = (8 * 7 * 3) / (16 * 15 * 14) = 168/3360 = 1/20
4 0
3 years ago
Arithmetic??????????????????
wel

good lesson and good day ^-^

7 0
3 years ago
HELP! Find the EXACT angle(s) on The Unit Circle (in radians) that would produce sinθ = −2√2
bazaltina [42]

Answer:

picture?

Step-by-step explanation:

4 0
3 years ago
The patient recovery time from a particular surgical procedure is normally distributed with a mean of 5.9 days and a standard de
FrozenT [24]
The 70th percentile is the same as the cutoff recovery time t such that every point above this time falls in the longest 30%, i.e.

\mathbb P(X>t)=0.30

Transform to the standard normal distribution:

\mathbb P\left(\dfrac{X-5.9}{2.5}>\dfrac{t-5.9}{2.5}\right)=\mathbb P(Z>t^*)

where t^* is the z-score corresponding to the cutoff time t, which is approximately t^*\approx0.5244. Solve for t:

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6 0
4 years ago
Using the pattern, give the coefficients of (x + y)^5 and (x + y)^6
musickatia [10]

Answer:

(x+y)^5=x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5

(x+y)^6=x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+y^6

Step-by-step explanation:

In order to find the values of (x+y)^5 and (x+y)^6, you need to apply the binomial theorem (high-level math you most likely don't need to worry about, it's easier than multiplying all the binomials together).

(x+y)^5 = \sum _{i=0}^5\binom{5}{i}x^{\left(5-i\right)}y^i = \frac{5!}{0!\left(5-0\right)!}x^5y^0+\frac{5!}{1!\left(5-1\right)!}x^4y^1+\frac{5!}{2!\left(5-2\right)!}x^3y^2+\frac{5!}{3!\left(5-3\right)!}x^2y^3+\frac{5!}{4!\left(5-4\right)!}x^1y^4+\frac{5!}{5!\left(5-5\right)!}x^0y^5 = x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5.

(x+y)^6 = \sum _{i=0}^6\binom{6}{i}x^{\left(6-i\right)}y^i = \frac{6!}{0!\left(6-0\right)!}x^6y^0+\frac{6!}{1!\left(6-1\right)!}x^5y^1+\frac{6!}{2!\left(6-2\right)!}x^4y^2+\frac{6!}{3!\left(6-3\right)!}x^3y^3+\frac{6!}{4!\left(6-4\right)!}x^2y^4+\frac{6!}{5!\left(6-5\right)!}x^1y^5+\frac{6!}{6!\left(6-6\right)!}x^0y^6= x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+y^6.

5 0
3 years ago
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