Ultraviolet light destroys which vitamin essential for cell division?

What happens to energy to during the formation of a soulotion

katen-ka-za [31]

<span>The main reason is the establishment of the steady state regime where the heat lost to the environment is compensating the heat injected to the system at the interface between the melt and the growing crystallites. At the very early stage of the crystallization process the transient regime dominates or appears which shows the local temperature variations more or less at the vicinity of the interface separating melt and solid phases. But this has very short duration depending upon the cooling rate, which is most control by the surrounding temperature (mold walls) and the heat conductivity of the growing crystal. </span>

5 0

3 years ago

Will binoculars work properly if their prisms (assume n = 1.50) are immersed in water (nwater= 1.33)? assume that binoculars wor

Amanda [17]

The binoculars will not work properly.

Please refer to the diagram attached.

Binoculars work on the principle of total internal reflection. The incident ray from air enters the prism through on face normally and it strikes the opposite face at an angle of 45°. The ray undergoes Total internal reflection if its critical angle is less than the angle of incidence,which , in this case is 45°.

The critical angle $i_{c}$ is related to the refractive index of the material of glass μ as shown below.

$\mu =\frac{1}{sini_c}$

For a refractive index equal to 1.5, the critical angle is found as shown below.

$sini_c=\frac{1}{\mu} \\ =\frac{1}{1.5} \\ =0.666$

Take the inverse of the value 0.666 to determine the critical angle.

$sin^{-1} (0.666)=41.8^o$

The critical angle in air is less than the angle of incidence, and hence total internal reflection occurs in air.

When the binoculars are immersed in water, the ray passes into the glass through water. therefore, the refractive index of the prism when immersed in water is given by,

$\mu_g_w=\frac{\mu_g}{\mu_w}$

Therefore the critical angle <em>c</em> in this case is given by,

$sinc=\frac{\mu_w}{\mu_g}$

Substitute 1.33 for $\mu_w$ and 1.5 for $\mu_g$ .

$sinc=\frac{\mu_w}{\mu_g} \\ =\frac{1.33}{1.5} \\ =0.8866$

Take the inverse of the value 0.8866.

$c=sin^{-1} (0.8866)\\ =62^o$

Since the critical angle of the prism when immersed in water, is 62°, which is greater than the angle of incidence of 45° required for viewing the object, the binoculars which are set for Total reflection in air, will not function when immersed in water.

4 0

4 years ago

Pls help‼️‼️I have no idea how to solve this question... Can someone pls help! :(

sdas [7]

Answer: Its dragon ball bro

Explanation: (To Ship Leesoo) "My name is Twenty-Fifth Baam. For short you can just call me Baam. Even if you tell me to introduce myself, there's not much to say. I don't have parents... or a home... a single set of dirty clothes is all I have. I always thought that I might die alone without ever being able to do anything... But now- I have friends. Thank you."[45]

(Response when put in a danger of death situation) "There is something I fear more than death."[46][47]

(To Androssi Zahard) "The heart moves where the heart wills."[48]

(To Yu Han Sung) "If Rachel isn't up there, that place is nothing more than a pile of garbage. No matter what's up there, that won't change. You told me that being like I am is strange, but to me, you're a person who can't even find a single thing that's precious within that huge pile of garbage."[49]

(To Androssi Zahard) "If I must fight, I will fight to protect what is precious to me."[48]

(To Hwa Ryun) "What's this rising emotion from my heart... I'm not sure... I have to find out...! Why... Rachel... betrayed... ME...!!"[50]

PART II

7 0

4 years ago

Read 2 more answers

On a frictionless horizontal air table, puck A (with mass 0.254 kg ) is moving toward puck B (with mass 0.367 kg ), which is ini

irinina [24]

Answer:

$v_a=0.8176 m/s$

$\Delta K=0.07969 J - 0.0849 J = -0.00521 J$

Explanation:

According to the law of conservation of linear momentum, the total momentum of both pucks won't be changed regardless of their interaction if no external forces are acting on the system.

Being $m_a$ and $m_b$ the masses of pucks a and b respectively, the initial momentum of the system is