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3 years ago

What happens to energy to during the formation of a soulotion

1 answer:

5 0

<span>The main reason is the establishment of the steady state regime where the heat lost to the environment is compensating the heat injected to the system at the interface between the melt and the growing crystallites. At the very early stage of the crystallization process the transient regime dominates or appears which shows the local temperature variations more or less at the vicinity of the interface separating melt and solid phases. But this has very short duration depending upon the cooling rate, which is most control by the surrounding temperature (mold walls) and the heat conductivity of the growing crystal. </span>

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Does the coefficient of kinetic friction depend on speed?

kolbaska11 [484]

It depends on speed because it is a part of a car

3 0

3 years ago

A 0.5 kg basketball moving 5 m/s to the right collides with a 0.05 kg tennis

Natali5045456 [20]

Answer:

A. 1.4 m/s to the left

Explanation:

To solve this problem we must use the principle of conservation of momentum. Let's define the velocity signs according to the direction, if the velocity is to the right, a positive sign will be introduced into the equation, if the velocity is to the left, a negative sign will be introduced into the equation. Two moments will be analyzed in this equation. The moment before the collision and the moment after the collision. The moment before the collision is taken to the left of the equation and the moment after the collision to the right, so we have:

$M_{before} = M_{after}$

where:

M = momentum [kg*m/s]

M = m*v

where:

m = mass [kg]

v = velocity [m/s]

$(m_{1} *v_{1} )-(m_{2} *v_{2})=(m_{1} *v_{3} )+(m_{2} *v_{4})$

where:

m1 = mass of the basketball = 0.5 [kg]

v1 = velocity of the basketball before the collision = 5 [m/s]

m2 = mass of the tennis ball = 0.05 [kg]

v2 = velocity of the tennis ball before the collision = - 30 [m/s]

v3 = velocity of the basketball after the collision [m/s]

v4 = velocity of the tennis ball after the collision = 34 [m/s]

Now replacing and solving:

(0.5*5) - (0.05*30) = (0.5*v3) + (0.05*34)

1 - (0.05*34) = 0.5*v3

- 0.7 = 0.5*v

v = - 1.4 [m/s]

The negative sign means that the movement is towards left

3 0

3 years ago

The image below shows two opposite forces acting on a rope, what can we say is true about the affect of the forces on the rope?

Tamiku [17]

It would be D) the rope is pulled to the right. This is because their is a greater force in that direction.

8 0

3 years ago

Read 2 more answers

A projectile is launched horizontally from a height of 8.0 m. The projectile travels 6.5 m before hitting the ground.

lozanna [386]

You can find

1) time to hit the ground
2) initial velocity
3) speed when it hits the ground

Equations

Vx = Vxo

x = Vx * t

Vy = Vyo + gt

Vyo = 0

Vy = gt

y = yo - Vyo - gt^2 / 2

=> yo - y = gt^2 / 2

1) time to hit the ground

=> 8.0 = g t^2 / 2 => t^2 = 8.0m * 2 / 9.81 m/s^2 = 1.631 s^2

=> t = √1.631 s^2 = 1.28 s

2) initial velocity

Vxo = x / t = 6.5m / 1.28s = 5.08 m/s

3) speed when it hits the ground

Vy = g*t = 9.81 m/s * 1.28s = 12.56 m/s

V^2 = Vy^2 + Vx^2 = (12.56 m/s)^2 + (5.08 m/s)^2 = 183.56 m^2 / s^2

=> V = √ (183.56 m^2 / s^2) = 13.55 m/s

7 0

3 years ago

A 2 kg ball travellng to the right with a speed of 4 m/s collidees with a 5 kg ball traveling to the left with a speed of 3 m/s.

Savatey [412]

Explanation:

Momentum before collision:

(2 kg) (4 m/s) + (5 kg) (-3 m/s) = -3 kg m/s

No external forces act on the balls, so momentum is conserved. Therefore, momentum after collision is also -3 kg m/s.

5 0

3 years ago