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Usimov [2.4K]
3 years ago
10

The star nearest to our sun is Proxima Centauri, at a distance of 4.3 light-years from the sun. How far away, in km, is Proxima

Centauri from the sun?
Physics
2 answers:
Cloud [144]3 years ago
5 0

Answer: 4.068(10)^{13} km

Explanation:

A light year is a unit of length and is defined as <em>"the distance a photon would travel in vacuum during a Julian year at the speed of light at an infinite distance from any gravitational field or magnetic field. </em>"

In other words: It is the distance that the light travels in a year.

This unit is equivalent to 9.461(10)^{12}km, which mathematically is expressed as:

1Ly=9.461(10)^{12}km

Doing the conversion:

4.3Ly.\frac{9.461(10)^{12}km}{1Ly}=4.068(10)^{13}km

DaniilM [7]3 years ago
5 0

The Answer: The star closest to our sun is 4.2 light years away from the sun.

Explanation:

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A child, hunting for his favorite wooden horse, is running on the ground around the edge of a stationary merry-go-round. The ang
olga55 [171]

Answer:

9.22 s

Explanation:

One-quarter of a turn away is 1/4 of 2π, or π/2 which is approximately 1.57 rad

Let t (seconds) be the time it takes for the child to catch up with the horse. We would have the following equation of motion for the child and the horse:

For the child: s_c = \omega_ct = 0.233t

For the horse: s_h = s_0 + a_ht^2/2 = 1.57 + 0.0136t^2/2 = 1.57 + 0.0068t^2

For the child to catch up with the horse, they must cover the same angular distance within the same time t:

s_c = s_h

0.233t = 1.57 + 0.0068t^2

0.0068t^2 - 0.233t + 1.57 = 0

t= \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

t= \frac{0.233\pm \sqrt{(-0.233)^2 - 4*(0.0068)*(1.57)}}{2*(0.0068)}

t= \frac{0.233\pm0.11}{0.0136}

t = 25.05 or t = 9.22

Since we are looking for the shortest time we will pick t = 9.22 s

6 0
3 years ago
Miles is camping in Glacier National Park. In the midst of a glacier canyon,
valentina_108 [34]

Answer:

t=1.623 sec

Explanation:

The distance traveled before the echo is had is:

distance=2d, d=280\ m\\\\=280\times 2\\\\=560 \ m

Given the speed of sound as v=345m/s, we use the speed equation to solve for t:

v=\frac{d}{t}\\\\345\ m/s=\frac{560m}{t}\\\\t=\frac{560}{360}\\\\=1.623 \ s

Hence, it takes 1.623 seconds to hear the echo.

8 0
3 years ago
They realize there is a thin film of oil on the surface of the puddle. If the index of refraction of the oil is 1.81, and they o
Sphinxa [80]

Answer:

The right solution is "165.8 nm".

Explanation:

Given:

Index of refraction,

n = 1.81

Wavelength,

λ = 600 nm

We know that,

⇒ t=\frac{\lambda}{2\times n}

By putting the values, we get

      =\frac{600}{2\times 1.81}

      =165.8 \ nm

3 0
3 years ago
How fast does sound travel? A. 1,115 feet per second B. 1,000 feet per second C. 2,000 feet per second D. 2,115 feet per second.
lys-0071 [83]

Answer:

A

Explanation:

6 0
3 years ago
The number of bacteria in a certain population increases according to a continuous exponential growth model, with a growth rate
sveta [45]

Answer:

It would take approximately 289 hours for the population to double

Explanation:

Recall the expression for the continuous exponential growth of a population:

N(t)=N_0\,e^{kt}

where N(t) measures the number of individuals, No is the original population, "k" is the percent rate of growth, and "t" is the time elapsed.

In our case, we don't know No (original population, but know that we want it to double in a certain elapsed "t". We also have in mind that the percent rate "k" would be expressed in mathematical form as: 0.0024 (mathematical form of the given percent growth rate).

So we need to solve for "t" in the following equation:

2\,N_0=N_0\,e^{0.0024\,t}\\\frac{2\,N_0}{N_0} =e^{0.0024\,t}\\2=e^{0.0024\,t}\\ln(2)=0.0024\,t\\t=\frac{ln(2)}{0.0024} \\t=288.811\,\, hours

Which can be rounded to about 289 hours

6 0
3 years ago
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