What is jdjxjcjxjckckckckv 2/3(I -6)=6
1 answer:
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Given:
The largest circle has a radius of R=7 units.
Let x be the radius of the large shaded circle.
The small shaded circles have a radius of 1/5 of the large shaded circle.
=> the small shaded circles have a radius of r=x/5
By adding up radii, we have the equation
2(r+x+r)=2(x/5+x+x/5)=2R=2*7=14
Simplify:
7x/5=14/2
x=5
=> r=1
Area of outer circle =
Area of large shaded circle =
Area of 4 small shaded circles =
Total area of shaded circles =
Shaded area as a fraction of that of the outer circle
The largest circle has a radius of R=7 units.
Let x be the radius of the large shaded circle.
The small shaded circles have a radius of 1/5 of the large shaded circle.
=> the small shaded circles have a radius of r=x/5
By adding up radii, we have the equation
2(r+x+r)=2(x/5+x+x/5)=2R=2*7=14
Simplify:
7x/5=14/2
x=5
=> r=1
Area of outer circle =
Area of large shaded circle =
Area of 4 small shaded circles =
Total area of shaded circles =
Shaded area as a fraction of that of the outer circle
The answer is D 40miles
The basic dimensions of any triangle are its area, base, and height.
They're related by the area equation; the area is half of the base times the height, or:
We know the area and the height, so the missing dimension has to be the base. Let's set up an equation by substituting the values the problem gives into the area equation.
Can you solve this equation for
?
They're related by the area equation; the area is half of the base times the height, or:
We know the area and the height, so the missing dimension has to be the base. Let's set up an equation by substituting the values the problem gives into the area equation.
Can you solve this equation for