What is jdjxjcjxjckckckckv<br> 2/3(I -6)=6

Coby needs to know the area and perimeter of his farm property. The length of his property is 1 6 mile and the width is 2 9 mile

Alexandra [31]

Answer:

P= 7/9 miles

A= (7/18) miles²

Step-by-step explanation:

Length 'l' = (1/6) mile

Width 'w'= (2/9) mile

Perimeter 'P' is given by:

'P' = 2l + 2w => 2(1/6) + 2(2/9)

P= 7/9 miles

Area 'A' is given by:

A= l x w =(1/6) x (2/9) = (7/18) miles²

3 0

3 years ago

Theater tickets for children cost $5.adult tickets cost $3 more . If 2 adults and 2 children buy theater tickets, what is the to

Nutka1998 [239]

5+5=10 - Children
5+3=8 - Adult
8+8=16
10+16-26

6 0

3 years ago

Nicole sold 1 cherry pie and 9 pumpkin pies for $60. Lisa sold 11 cheery pies and 4 pumpkin pies for $90. what's the cost each o

zubka84 [21]

X= cost per cherry pie
y= cost per pumpkin pie

NICOLE
1x + 9y= $60

LISA
11x + 4y= $90

STEP 1
multiply Nicole's equation by -11

-11(1x + 9y)= -11($60)
multiply -11 by all terms

(-11 * x) + (-11 * 9y)= (-11 * 60)

-11x - 99y= -660

STEP 2
add Nicole's new equation from step 1 to Lisa's equation to solve for y (using the elimination method)

-11x - 99y= -660
11x + 4y= 90
the x terms "cancel out"

-95y= -570
divide both sides by -95

y= $6 per pumpkin pie

STEP 3
substitute y value into either original equation to solve for x

x + 9y= $60

x + 9(6)= 60

x + 54= 60
subtract 54 from both sides

x= $6 per cherry pie

CHECK
11x + 4y= $90
11(6) + 4(6)= 90
66 + 24= 90
90= 90

ANSWER: Each cherry pie costs $6 and each pumpkin pie costs $6.

Hope this helps! :)

3 0

3 years ago

A study was conducted to determine whether magnets were effective in treating pain. The values represent measurements of pain us

amm1812

Answer:

Given:

Sham: n= 20, x=0.44, s=1.24,

Magnet:n= 20, x =0.49, s= 0.95

For Sham:

Sample size, n = 20

Sample mean = 0.44

Standard deviation = 1.24

For Magnet:

Sample size = 20

Sample mean = 0.49

Standard deviation = 0.95

The null and alternative hypotheses:

H0: s1²=s2²

H1: s1² ≠ s2²

a) To find the test statistics, use the formula:

$\frac{s1^2}{s2^2}$

$\frac{1.24^2}{0.95^2} = \frac{1.5376}{0.9025} = 1.7037$

Test statistics = 1.7037

b) P-value:

Sham: degrees of freedom $= n - 1 = 20 - 1 = 19$

Magnet: degrees of freedom $= n - 1 = 20 - 1 = 19$

The critical values:

[Za/2, df1, df2)], [(1 - Za/2), df1, df2]

$f[0.05/2, 19, 19], f[(1 - 0.05/2), 19, 19]$

$f[0.025, 19, 19], f[0.975, 19, 19]$

$(2.526, 0.3958)$

The rejection region:

Reject H0, if F < 0.3958 or if F > 2.526

c) Conclusion:

Since the critical values of test statistic is between (0.3958 < 1.7037 < 2.526), we fail to reject null hypothesis H0.

There is insufficient evidence to to support the claim that those given a sham treatment have reductions that vary more than those treated with magnets

3 0

3 years ago

The mean (average) of 4 numbers is 88.

adoni [48]

Here is your answer mate✌️

3 0

3 years ago

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What is jdjxjcjxjckckckckv 2/3(I -6)=6