this is a binomial problem: p = 0.7 and q = 0.3
a) (0.7)^6
b) (6C4)(0.7)^4(0.3)^2
c) Pr ( at least 4) = Pr(4) + Pr(5) + Pr(6) = (6C5)(0.7)^5(0.3) + (0.7)^6
d) Pr (no more than 4) = 1 - Pr(at least 4) = 1 - (answer from c)
The total number of pieces of chalk in the classroom will be the number of pieces in the 4 boxes in addition to the six individual pieces.
The average box of chalk holds 12 pieces of chalk
This means that 4 boxes have 12*4 = 48 pieces
Total number of pieces = 48 + 6 = 54 pieces of chalk
Answer:
18
Step-by-step explanation:
The LCD of 6 and 9 is 18.
6: 6, 12, 18
9: 9, 18
Since they meet at the $105 mark the answer would be $105
