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Serhud [2]
3 years ago
11

30 points :)

Mathematics
1 answer:
harina [27]3 years ago
5 0
Take this with a grain of salt as I just failed my math test

9.99 + 0.35t ≤ 12

12 - 9.99 = 0.35t (at its most)
2.01 = 0.35t
Rounded down, 2.01 / 0.35 = 5
5 toppings
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What is the approximate volume of a cone with a height of 11 ft and radius of 3 ft?
nadya68 [22]
Substitute the values of the radius <span>(<span><span>r=3</span>),</span></span><span> the </span>height <span>(<span><span>h=11</span>),</span></span><span> and an approximation of </span>Pi <span>(<span>3.14)</span></span><span> into the </span>formula<span> to find the </span>volume<span> of the </span>cone<span>.
</span><span>V≈+<span>1/3</span>⋅3.14⋅<span>3^2</span>⋅11

</span><span>Simplify.
</span>Write 3.14<span> as a </span>fraction<span> with </span>denominator <span>1.</span><span> 
</span><span>V≈+<span>1/3</span>⋅<span>3.14/1</span></span> <span>

</span>Combine <span>1/3</span><span> and </span><span>3.14/1</span><span> to get </span><span><span>3.14/3</span>.</span><span> 
</span><span>V≈+<span>3.14/3</span></span><span> 
</span>
Replace back in to larger expression<span>. 
</span><span>V≈+<span>3.14/3</span>⋅<span>3^2</span>⋅11</span><span> 
</span>
Divide 3.14<span> by </span>3<span> to get </span><span>1.04666667.
</span><span>V≈+1.04666667⋅<span>3^2</span>⋅11

</span>Raise 3<span> to the </span>power<span> of </span>2<span> to get </span><span>9.
</span><span>V≈+1.04666667⋅9⋅11

</span>Multiply 1.04666667<span> by </span>9<span> to get </span><span>9.42.
</span><span>V≈+9.42⋅11

</span>Multiply 9.42<span> by </span>11<span> to get </span><span>103.62.
</span><span>V≈+103.62

</span>Remove trailing zeros<span> from </span><span>103.62.
</span><span>V≈+103.62</span><span>f<span>t^3

Volume:
</span></span>V≈+103.62ft^3
8 0
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mart [117]
G(x)=4x
g(a)=32

32=4x
X=8
g(8)=32

a=8
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11Alexandr11 [23.1K]

Answer:

X = 0

Step-by-step explanation:

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Answer:

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